Solve for W in A = 2(L + W)
1 answer:
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Answer:
The ans is in the picture with the steps how i got it
(hope this helps can i plz have brainlist :D hehe)
Step-by-step explanation:
Answer:
Step-by-step explanation:
2 cos x + √ 2 = 0
2 cos x = -√ 2
cos x = -√ 2 / 2
x = arcCos( -√ 2 / 2 )
so to solve we have to use "co-terminal " angles .. do you know what I'm saying? do you understand the words coming out of my mouth :DDDDD OKay back to math and not movie lines .. :P
x = arcCos( √ 2 / 2 )
x = 45 °
now find the "co terminal" angle that is on 45 ° but in the correct quadrant... since the -√ 2 is negative.. we now that we go down the y axis.. but also positive on the x axis.. soooo.. that put the angle in the 4th quadrant... so this is an angle of 315° if we go in the CCW ( counter clock wise ) direction but it's also -45° in the CW (clock wise ) direction
below is the table to remember the trig special angles
notice how it's 1,2,3,4 .. so it's super easy to remember.. the trig books don't show you this "trick" :P
copy and paste this to your computer some where handy
Sin(0) = 0/2 =0
Sin(30)= /2 = 1/2
Sing(45) =/2 =
/2
Sin(60)=/2 =
/2
Sin(90)=/2 = 1
Cos is exactly the same but counts backwards from 90°
Cos(90) = 0/2 = 0
Cos(60) = /2 = 1/2
Cos(45) = /2 =
/2
Cos(30) = /2 =
/2
Cos(0) = /2 = 1
Answer:
Step-by-step explanation:
Notice that the focus is a points on the vertical axis, that means the parabolla opens vertically, and has the form
Because the parameter is positive and equal to 0.75. Additionally, the vertex is at the origin, that's why the equation is this simple.
Replacing the parameter value, we have
Therefore, the equation of a parabolla with vertex at the origin and focus at (0, 0.75) is .