Evaluate log base 16 0.25

Mathematics

1 answer:

AveGali [126]3 years ago

5 0

Answer:

Step-by-step explanation:

Rewrite log16(0.25)

using the change of base formula.

Exact Form:

log(0.25)log(16)

Decimal Form:

−0.5

You might be interested in

Before an election 23% said that would vote for A 9% said they would vote for B 20% said they would not vote these all votes as

Bad White [126]

A got the most votes because the ration works with the percentage very well

7 0

3 years ago

There are 5,426 people seated at tables. Each table seats 8 people.

ddd [48]

Answer:

678

679

Step-by-step explanation:

Number of people: 5426

Capacity of table: 8

How many tables are full?

Number of full tables= 5426/8= 678.25 so full part is 678

How many people are sitting at a table that is not full?

0.25 table= 8*0.25= 2 people are sitting at a table that is not full

5426 - 678*8= 2 people

How many tables are needed for all 5,426 people?

678+1= 679 tables

6 0

3 years ago

Can someone help me with this?

podryga [215]

The pink goes under the light blue then the dark blue goes under the pink cause it says finish :)

4 0

2 years ago

Read 2 more answers

Number 2 I need help on how to solve it

Hunter-Best [27]

Let's simplify the following expression:

$\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}$

We get,

$\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}$ $\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}$