Answer:
- 3.75 bags of ChowChow
- 0.75 bags of Kibble
Step-by-step explanation:
The constraints on protein, minerals, and vitamins give rise to the inequalities ...
40c +30k ≥ 150 . . . . . . required protein
20c +20k ≥ 90 . . . . . . required minerals
10c +30k ≥ 60 . . . . . . . required vitamins
And we want to minimize 10c +12k.
The graph shows the vertices of the feasible region in (c, k) coordinates. The one that minimizes cost is (c, k) = (3.75, 0.75).
To minimize cost, the daily feed should be ...
- 3.75 bags of ChowChow
- 0.75 bags of Kibble
Daily cost will be $46.50.
A=1/2bh
b=8+h
A=384
384=1/2(bh)
times 2
768=bh
sub
768=b(8+b)
768=8b+b^2
minus 768 both sides
0=b^2+8b-768
factor
0=(b-24)(b+32)
set to zero
b-24=0
b=24
b+32=0
minus 32
b=-32
false, legnths cannot be negative
b=24
24=8+h
minus 8
16=h
base=24ft
altetude=16ft
Answer:
Literally take your f(x) and - your g(x)
(x^2+9x+18) - (x + 6)
Remember to distribute the negative sign.
Answer:
612 adults
361 students
Step-by-step explanation:
To solve this question, set two equations:
Let x be number of adults and y be number of students.
As there are in total 937 people, the equation would be the sum of both adults and children:
...... ( 1 )
As the total sale amount is $1109, the equation would be to add up the ticket fee:
...... ( 2 )
Put ( 1 ) into ( 2 ):
Put y into ( 1 ):
Therefore there are 612 adults and 361 students.
I think u just subtract 35° from 130° and that should be the angle of x
