The sides of a rhombus with angle of 60° are 6 inches. Find the area of the rhombus.

2 answers:

4 0

Sorry I'm not too sure but I know that you can probably find it using this formula:
Area = (1/2)(a)(b)(sin(C)) with C being the angle in the middle of both lines a and b in a triangle

Since a rhombus is pretty much two similar triangles....
Area = ((1/2)(6)(6)(sin6)) x 2
should give you the exact area

Sorry that I couldn't give an exact answer, I'm not too sure what in is because we were probably not taught the same things. Does it mean inch or is it supposed to be Ln? Anyways, whatever it means, maybe you could calculate each option's value and see which one is the same answer as the calculation I talked about above?

cricket20 [7]3 years ago

3 0

Answer:

18 to the square root of 3in2

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What is 6x^2-2x+1=0 plz help

Kazeer [188]

6x^2 - 2x + 1 is a quadratic formula from the form ax^2 + bx + c. This form of equation represents a parabola.
Finding 6x^2 - 2x + 1 = 0, means that you need to find the zeroes of the equation.
Δ = b^2 - 4ac
If Δ>0, the equation admits 2 zeroes and 6x^2 - 2x + 1 = 0 exists for 2 values of x.
If Δ<0, the equation doesn't admit any zero, and 6x^2 - 2x + 1 = 0 doesn't exist since the parabola doesn't intersect with the axe X'X
If Δ=0, the equation admits 1 zero, which means that the peak of the parabola is touching the axe X'X.

In 6x^2 - 2x + 1, a=6, b=-2, and c =1.
Δ= b^2 - 4ac
Δ=(-2)^2 - 4(6)(1)
Δ= 4 - 24
Δ= -20
Δ<0 so the parabola doesn't intersect with the Axe X'X, which means there's no solution for 6x^2 - 2x + 1 = 0.

I've added a picture of the parabola represented by this equation under the answer.

Hope this Helps! :)