Answer:
(3, 4 )
Step-by-step explanation:
3x - y = 5 → (1)
x + y = 7 → (2)
adding the 2 equations term by term will eliminate y
4x + 0 = 12
4x = 12 ( divide both sides by 4 )
x = 3
substitute x = 3 into either of the 2 equations and solve for y
substituting into (2)
3 + y = 7 ( subtract 3 from both sides )
y = 4
solution is (3, 4 )
Answer:
a) Real range of employees hired by each organization surveyed = 56
b) The cumulative percent of "new" employees with the lowest tenure = 30%
Step-by-step explanation:
a) Note: To get the real range of employees hired by each organization, you would do a head count from 34 to 89 employees. This means that this can be done mathematically by finding the difference between 34 and 89 and add the 1 to ensure that "34" is included.
Real range of employees hired by each organization surveyed = (89 - 34) + 1
Real range of employees hired by each organization surveyed = 56
b) It is clearly stated in the question that the "new" employee status was mostly reserved for the 30% of employees in the organization with the lowest tenure.
Therefore, the cumulative percent of "new" employees with the lowest tenure = 30%
2x+3x+2=-4(cause y=3x+2)
5x=-6
x=-6/5
f(-6/5)=-8/5
negative 6 over 5
Rise: 7, Run: 0
Rise (on the y-axis); from -2 to 5
Run (x-axis): 0
Step-by-step explanation:
Assuming the data is as shown, restaurant X has a mean service time of 180.56, with a standard deviation of 62.6.
The standard error is SE = s/√n = 62.6/√50 = 8.85.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
180.56 ± 1.960 × 8.85
180.56 ± 17.35
(163, 198)
Restaurant Y has a mean service time of 152.96, with a standard deviation of 49.2.
The standard error is SE = s/√n = 49.2/√50 = 6.96.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
152.96 ± 1.960 × 6.96
152.96 ± 13.64
(139, 167)
