Answer:
8100 is the smallest perfect square divisible by 5,6 and 27
Step-by-step explanation:
5 = 5 * 1
6 = 2 * 3
27 = 3 * 3 *3
5 * 6 * 27 = 2 * 3 * 3 * 3 * 3 * 5
Factors of perfect square will be perfect squares
To make this a perfect, multiply by 5 * 2
Perfect square = 5 * 6 * 27 * 5 * 2
= 8100
, which is the square of .
Factor the three divisors into prime numbers:
Any number divisible by these three divisors should include the following factors:
Note that all these three prime factors have an odd power (, , and , respectively)
The product of these three factors would be:
.
Indeed, is divisible by all these three divisors. At the same time, because all the powers of its prime factors are even,
B or C i think...let me know if im wrong
g = 1, 3
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
<u>Step 1: Define</u>
<em>Identify</em>
g² - 4g = -3
<u>Step 2: Solve for </u><em><u>g</u></em>