The probability that the 10th will be able to sit on his/her original seat when the 1st person has randomly changed his/her seat is 7/9
Probability :
In Mathematics, Probability stands for the ratio of the number of favorable outcomes to the total number of outcomes in a random experiment. It is used to predict how likely an event can happen.
Probability of an event,
P(E) = No of favorable outcomes / total number of outcomes
Here we have,
10 people always get on a bus in the same order and sit in the same places.
The 1st person has randomly changed his/her seat
Except for 1 remaining number of seats is 9
If 1st person changes his/her place with the remaining 9 seats the number of ways that 1st person can be seated is 9
In 9 ways 10th will be able to sit on his/her original seat when the 1st person is seated in 2 to 9 seats i.e 7 seats
Therefore,
The number of favorable outcomes that the 10th person will be able to seat in his/her original seat = 7
From the above observations,
The probability that the 10th will be able to sit on his/her original seat
= 7 / 9
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The answer for this will be
2a(1-2a ²+3bc)
Answer:
Step-by-step explanation:
Let the age be xy or 10x + y.
Reverse the two digits of my age, divide by three, add 20, and the result is my age, convert this to equation:
- (10y + x)/3 + 20 = 10x + y
- (10y + x)/3 = 10x + y - 20
- 10y + x = 3(10x + y - 20)
- 10y + x = 30x + 3y - 60
- 30x - x + 3y - 10y = 60
- 29x - 7y = 60
We should consider both x and y are between 1 and 9 since both the age and its reverse are 2-digit numbers.
Possible options for x are:
- 29x ≥ 7*1 + 60 = 67 ⇒ x > 2, at minimum value of y,
and
- 29x ≤ 7*9 + 60 = 123 ⇒ x < 5, at maximum value of y.
So x can be 3 or 4.
<h3>If x = 3</h3>
- 29*3 - 7y = 60
- 87 - 7y = 60
- 7y = 27
- y = 27/7, discarded as fraction.
<h3>If x = 4</h3>
- 29*4 - 7y = 60
- 116 - 7y = 60
- 7y = 56
- y = 8
So the age is 48.
Answer:
4
Step-by-step explanation:
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