Answer:
Step-by-step explanation:
AR = QR = RS = (1/2) QS = 3
So ....by the Pythagorean Theorem, AS = AQ =
√ [3^2 + 3^2] = √[9 + 9 ] = √18
And the area of the two semi-circles= the area of a circle with a radius of AS/2 =
pi [AS/2]^2 =
pi [√18/2]^2 = 18pi/4 = (9/2)pi units^2
And the area of the rest of the figure is just that of a rhombus =
The product of the diagonals / 2 =
AB*QS/2 = 9 * 6 / 2 = 27 units^2
So....the total area =
[(9/2) pi + 27] units^2 = about = 41.1 units^2 [rounded]
