Step-by-step explanation:
0.08*300 + 0.13x = 51.95
Multiply thru by 100 to get:
8*300 + 13x = 5195
13x = 5195-2400
13x = 2,795
x = 215 hours
Answer:
The wall is 10.5 foot far from the bottom of the ladder.
Step-by-step explanation:
Given:
Height of the ladder leaning against wall (Hypotenuse) = 20 foot.
Height from where the window is above from the ground (Leg1) = 17 feet.
To find the distance of the bottom of the ladder far from the wall (Leg2) = ?
Now, by using the pythagorean theorem:
by squaring both sides
10.535 foot rounded nearest tenth is 10.5 foot.
Therefore, the wall is 10.5 foot far from the bottom of the ladder.
Answer:
case 2 with two workers is the optimal decision.
Step-by-step explanation:
Case 1—One worker:A= 3/hour Poisson, ¡x =5/hour exponential The average number of machines in the system isL = - 3. = 4 = lJr machines' ix-A 5 - 3 2 2Downtime cost is $25 X 1.5 = $37.50 per hour; repair cost is $4.00 per hour; and total cost per hour for 1worker is $37.50 + $4.00
= $41.50.Downtime (1.5 X $25) = $37.50 Labor (1 worker X $4) = 4.00
$41.50
Case 2—Two workers: K = 3, pl= 7L= r= = 0.75 machine1 p. -A 7 - 3Downtime (0.75 X $25) = S J 8.75Labor (2 workers X S4.00) = 8.00S26.75Case III—Three workers:A= 3, p= 8L= ——r = 5- ^= § = 0.60 machinepi -A 8 - 3 5Downtime (0.60 X $25) = $15.00 Labor (3 workers X $4) = 12.00 $27.00
Comparing the costs for one, two, three workers, we see that case 2 with two workers is the optimal decision.
My teacher taught me to make an imaginary decimal and 0 at the beginning of the number and then move the decimal to the end of the number... idk that may be the wrong way to do it but you can try :/
