1/2y^2=1/2x^2+8. The curve's slope at (x,y) is x/y, so dy/dx=x/y. To solve this differential equation, rearrange it to: y*dy=x*dx, and by integrating both sides, we get 1/2y^2=1/2x^2+C (some constant). Plug in (0,4) into this equation, 8=0+C, so C=8. The curve's equation is 1/2y^2=1/2x^2+8.
Do you mean y = mx + b instead of y = mc + b? In that case:
b in y = mx + b format is the y-intercept, as this kind of equation is called slope-intercept form.
These are the two equation
10-2
13-5
Answer:
Step-by-step explanation:
you have to multiply
8 + 3 (4 - n )
n= 3
8 + 3( 4-3)
8 + 3 * 1
8 + 3 = 11