Which is the reflection line for the transformation

Solve the question below 77

Vadim26 [7]

Answer:

<em>The height of the monument is 124.8 ft</em>

Step-by-step explanation:

<u>Right Triangles</u>

The ratios of the sides of a right triangle are called trigonometric ratios. The tangent ratio is defined as:

$\displaystyle \tan\theta=\frac{\text{opposite leg}}{\text{adjacent leg}}$

The figure attached below shows the different distances involved in the problem. We heed to find the value of h, the height from Daniel's eyes. Then we'll add it to the 6 ft where his eyes are located from the ground.

Taking the angle of 68° as a reference:

$\displaystyle \tan 68^\circ=\frac{h}{48}$

Solving for h:

$\displaystyle h=48\tan 68^\circ$

Calculating:

h = 118.8 ft

The height of the monument is 118.8 ft + 6 ft = 124.8 ft

6 0

3 years ago

Find an exact value cos(19pi/12)

dmitriy555 [2]

$cos\left ( \frac{9\pi}{12}\right )=\frac{\sqrt{2-\sqrt{3}}}{2}$

Step-by-step explanation:

We know that

cos 2x = 2cos²x - 1

So we have

$cosx=\sqrt{\frac{1+cos2x}{2}}$

Substituting $x=\frac{19\pi}{12}$

$cos\left ( \frac{19\pi}{12}\right )=\sqrt{\frac{1+cos2\left ( \frac{19\pi}{12}\right )}{2}}\\\\cos\left ( \frac{19\pi}{12}\right )=\sqrt{\frac{1+cos\left ( \frac{19\pi}{6}\right )}{2}}\\\\cos\left ( \frac{9\pi}{12}\right )=\sqrt{\frac{1+cos570}{2}}\\\\cos\left ( \frac{9\pi}{12}\right )=\sqrt{\frac{1-\frac{\sqrt{3}}{2}}{2}}\\\\cos\left ( \frac{9\pi}{12}\right )=\sqrt{\frac{2-\sqrt{3}}{4}}\\\\cos\left ( \frac{9\pi}{12}\right )=\frac{\sqrt{2-\sqrt{3}}}{2}$

$cos\left ( \frac{9\pi}{12}\right )=\frac{\sqrt{2-\sqrt{3}}}{2}$

3 0

3 years ago

Read 2 more answers

Susie is paying $540.15 every month for her $150,000 mortgage. If this is a 30 year mortgage, how much interest will she pay ove

GuDViN [60]

Answer:

17310.6

$540.15 multiply 30

because if they ask all in every month is 540.15

and she got 30 year

6 0

3 years ago

I beg please help :(

Aloiza [94]

Answer:

(2.8, 0.8)

(0.8, -1.8)

Step-by-step explanation:

1. Home (Xa, Ya)= (8, 6)

San Antonio (Xb, Yb)=(-5, -7)

Xa-Xb=8-(-5)=13

Ya-Yb=6-(-7)=13

Emily starts at 2/5 of the road, make it (Xc, Yc)

Xc= Xa-(Xa-Xb)2/5=8-5.2=2.8

Yc=Ya-(Ya-Yb)2/5=6-5.2=0.8

=> Emily starts at (2.8, 0.8)

2.

Emily ends at 3/5 of the road, , make it (Xd, Yd)

Xd= Xa-(Xa-Xb)3/5=8-7.8=0.8

Yd=Ya-(Ya-Yb)3/5=6-7.8=-1.8

=> Emily ends at (0.8, -1.8)

6 0

3 years ago

Please show your work and I will make you brainliest

klio [65]

Answer:

17. y=1/2x+5

18. y=-2x+15

19. y=2x-7

Step-by-step explanation:

Number 17.

(4,7); parallel to y=1/2x-1

You know that lines that are parallel to each other have the same slope, so the slope is 1/2x.

1. Use the point-slope formula to solve for the slope-intercept equation.

y-y1=m(x-x1)

m= 1/2

x= 4

y= 7

y-7= 1/2(x-4)

y-7= 1/2x-2

y=1/2x+5

Number 18.

(4,7); perpendicular to y=1/2x-1

You know that lines that are perpendicular to each other have the opposite reciprocal slope, so the slope is -2.

1. Use the point-slope formula to solve for the slope-intercept equation.

y-y1=m(x-x1)

m= -2

x= 4

y= 7

y-7=-2(x-4)

y-7=-2x+8

y=-2x+15

Number 19.

f(3)=-1

f(4)=1

To write a linear equation, first find the slope with the slope formula.

x1= 3

y1= -1

x2= 4

y2=1

(y2-y1)/(x2-x1)

(1-(-1))/(4-3)

2/1

m=2

Use the point-slope formula and solve for the slope-intercept equation.

y-y1=m(x-x1)

y-1=2(x-4)

y-1=2x-8

y=2x-7

6 0

3 years ago