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3 years ago

ABCD is a parallelogram.

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

7 0

Answer:

Using SAS they are congruent.

Step-by-step explanation:

E is the point where the diagonals AC and BD meet.

Side: AB = CD

Angle: ∠ABE = ∠EDC

Side: BE = DE

Hence by SAS theorem the two triangles are congruent.

Orlov [11]3 years ago

6 0

Answer and Step-by-step explanation:

Because this is a parallelogram, by definition, the intersection point of the two diagonals bisects them, making AE = CE and BE = DE.

We also know that ∠AEB = ∠CED because they're vertical angles, so by definition, they're congruent.

Thus, we can use the side-angle-side (SAS) congruency theorem to prove that ΔABE ≅ ΔCDE.

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storchak [24]

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$\large\boxed{h=5.488\ in}$

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$A=bh$

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base₁ = 9.8 in

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