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Nastasia [14]
3 years ago
14

What is the operation per 1000 gallons

Mathematics
1 answer:
mezya [45]3 years ago
4 0

Answer:

METER SIZE BI-MONTHLY USAGE INCLUDED IN MINIMUM BI-MONTHLY MINIMUM CHARGES RATE PER 1000 GALLONS

3/4″ Residential 5,000 gallons $18.00 $3.60

3/4″ Commercial 8,000 gallons $28.80 $3.60

1″ 20,000 gallons $72.00 $3.60

1 1/2″ 40,000 gallons $144.00 $3.60

2″ 64,000 gallons $230.40 $3.60

3″ 128,000 gallons $460.80 $3.60

4″ 200,000 gallons $720.00 $3.60

6″ 400,000 gallons $1,440.00 $3.60

8″ 640,000 gallons $2,304.00 $3.60

10″ 920,000 gallons $3,312.00 $3.60

Multifamily per residential unit 5,000 gallons per unit $18.00 per unit $3.60


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Akimi4 [234]

Answer:

23.92

Step-by-step explanation:

You can round 2.99 to 3 and do 3x8 mentally then subtract 8 cents ¯\_(ツ)_/¯

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2 years ago
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Which choice is the solution to the inequality below?
Georgia [21]
<h3>hello!</h3>

In order to solve this inequality, we should divide both sides by 9:-

\sf{9x < 72}

Why 9? Because x is multiplied by 9, and we need to isolate x in order to find its value.

\sf{x < 8}

Hence, that's the solution to the inequality.

<em>It also means that the numbers less than 8 will satisfy the given inequality (make the inequality true)</em>

(Option C is correct :) )

<h3>note:-</h3>

Hope everything is clear; if you need any explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)

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2 years ago
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Three planets are in line and are orbiting round a sun, one take 1 week to orbit the sun another takes 9 weeks and the other tak
patriot [66]

Answer:

27 weeks.

Step-by-step explanation:

You need to calculate the minimun common multiple between the three times.

1 week = 1^1 week

9 weeks = 3^2 weeks

27 weeks = 3^3 weeks

You take the 1 and the 3 with the biggest exponent and multiply. In this case is 1^1*3^3 = 27. So, in 27 weeks the pkanets will all be in alignment.

7 0
3 years ago
What is the absolute value of 19.8?
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Step-by-step explanation:

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2 years ago
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In ΔOPQ, o = 9.2 cm, p = 2.4 cm and ∠Q=37°. Find the length of q, to the nearest 10th of a centimeter.
storchak [24]

The length of q, to the nearest 10th of a centimeter is 7.6 cm.

Given in question,

In ΔOPQ,

o = 9.2 cm

p = 2.4 cm

∠Q = 37°

Cosine formula ⇒ cos θ = \frac{o^{2}+p^{2}-q^{2}  }{2op}

Putting the values in equation,

       cos 37 = \frac{(9.2)^{2}+(2.4)^{2}-q^{2}  }{2*9.2*2.4}

         0.799 = \frac{84.64 + 5.76-q^{2} }{44.16}

0.799*44.16 = 90.4 - q^{2}

         32.28 = 90.4 - q^{2}

                q^{2} = 90.4 - 32.28

                q^{2} = 58.12

                 q = \sqrt{58.12}

                 q = 7.63

q = 7.6 cm (to nearest 10th)

Hence, length of q is 7.6 cm.

Learn more about length on:

brainly.com/question/8552546

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