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3 years ago

DF=78, DE=5x-9, and EF-2x+10, find EF

Mathematics

1 answer:

lbvjy [14]3 years ago

8 0

Answer:

As e is point between df. So we can write df as

df = de + ef

As given df = 78 , de = 5x - 9 , ef = 2x + 10.

So we can write

78 = 5x - 9 + 2x + 10

78 = 7x + 1

On subtracting 1 on booth side

78 - 1 = 7x +1 - 1

77 = 7x

On dividing both side by 7.

11 = x

So x = 11.

So ef = 2x + 10 = 2*11 + 10 = 22 + 10 = 32

Step-by-step explanation:

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3 years ago

URGENT! 40 POINTS! PLEASE HELP!

umka2103 [35]

Answer:

(a) $8 x(5 x-6)=40 x^{2}-48 x$

Step-by-step explanation:

(a) To find verify the answer we need to multiplying the equation $8 x(5 x-6)$

$8 x(5 x-6)=40 x^{2}-48 x$

Thus, this statement is true.

(b) To find verify the answer we need to multiplying the equation $-4 x\left(2 x^{2}+1\right)$

$-4 x\left(2 x^{2}+1\right)=-8 x^{3}-4 x$

Hence, the given statement is false.

$\begin{aligned}(x-3)(5 x-6) &=5 x^{2}-6 x-15 x+18 \\&=5 x^{2}-21 x+18\end{aligned}$

Hence, the given statement is true.

(d) To find verify the answer we need to multiplying the equation $(2 x+3)\left(x^{2}+3 x-5\right)$

$\begin{aligned}=(2 x+3)\left(x^{2}+3 x-5\right) &=2 x^{3}+6 x^{2}-10 x+3 x^{2}+9 x-15 \\&=2 x^{3}+9 x^{2}-x-15\end{aligned}$

Hence, the given statement is false.

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3 years ago

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evablogger [386]

Answer:

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Step-by-step explanation:

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