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Black_prince [1.1K]
3 years ago
10

Which statement best compares a line and a point

Mathematics
1 answer:
Volgvan3 years ago
6 0
A line has 0 endpoints and extends forever in 2 directions and a point has 1 endpoint and extends forever in 0 directions.
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 GIVING BRAINLIEST TO THE PERSON THAT CAN EXPLAIN THIS THE BEST (:
scZoUnD [109]

Answer:

14w

Step-by-step explanation:

Width = w

Length is 6 time its width. so, multiply w by 6

length = 6*w = 6w

Perimeter of rectangle = 2* (length + width)

                                        = 2*(6w + w)

                                        = 2*7w

                                         = 14w

4 0
1 year ago
Find the simple interest on $2,219 principal, deposited for 6 years at a rate of 1.91%
Aleks04 [339]

Answer:

$13,568.30

Step-by-step explanation:

I = Prt

I = 2,219(1.0191)(6) = 13,568.30

6 0
3 years ago
(9) power 3 +(3) power 2+(6) power 3+(15)power 2=?
Kisachek [45]
Hey! So, here's a tip. When writing exponents, an easier way is to write a^b, rather than a to the b power. Besides that, here is your answer!


So-------

9^3=729

3^2=9

6^3=216

15^2=225



Now that we have that figured out, we can add them together, wish is simple. 729 + 9 + 216 + 225= 1,179.



Therefore, your final answer will be 1,174.




If you have any questions on this, I'm happy to help you. :)
5 0
2 years ago
An article reports that 1 in 500 people carry the defective gene that causes inherited colon cancer. In a sample of 2000 individ
Tema [17]

Answer:

a) P=0.558

b) P=0.021

Step-by-step explanation:

We can model this random variable as a Poisson distribution with parameter λ=1/500*2000=4.

The approximate distribution of the number who carry this gene in a sample of 2000 individuals is:

P(x=k)=\frac{\lambda^ke^{-\lambda}}{k!} =\frac{4^ke^{-4}}{k!}

a) We can calculate that the approximate probability that between 4 and 9 (inclusive) as:

P(4\leq x\leq 9)=\sum_{k=4}^9P(k)\\\\\\ P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\P(9)=4^{9} \cdot e^{-4}/9!=262144*0.0183/362880=0.013\\\\\\

P(4\leq x\leq 9)=\sum_{k=4}^9P(k)=0.195+0.156+0.104+0.060+0.030+0.013=0.558

b) The approximate probability that at least 9 carry the gene is:

P(x\geq9)=1-P(x\leq 8)\\\\\\

P(0)=4^{0} \cdot e^{-4}/0!=1*0.0183/1=0.018\\\\P(1)=4^{1} \cdot e^{-4}/1!=4*0.0183/1=0.073\\\\P(2)=4^{2} \cdot e^{-4}/2!=16*0.0183/2=0.147\\\\P(3)=4^{3} \cdot e^{-4}/3!=64*0.0183/6=0.195\\\\P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\

P(x\geq9)=1-P(x\leq 8)\\\\P(x\geq9)=1-(0.018+0.073+0.147+0.195+0.195+0.156+0.104+0.060+0.030)\\\\P(x\geq9)=1-0.979=0.021

8 0
2 years ago
Find f^3(x) for f(x)=4/x^2
vaieri [72.5K]

Answer:

  f³(x) = 64/x⁶

Step-by-step explanation:

  f³(x) = (f(x))³ = (4/x²)³ = 4³/(x²)³

  f³(x) = 64/x⁶

_____

The applicable rules of exponents are ...

  (a/b)^c = (a^c)/(b^c)

  (a^b)^c = a^(bc)

7 0
3 years ago
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