3 years ago

Which statement best compares a line and a point

1 answer:

Volgvan3 years ago

6 0

A line has 0 endpoints and extends forever in 2 directions and a point has 1 endpoint and extends forever in 0 directions.

You might be interested in

Recall that a right triangle is a triangle with one right angle.one angle of the triangle measures 89.99 degrees.can the triangl

Shtirlitz [24]

Yes because you only need a 90 degree to become a right

4 0

3 years ago

Which values are solutions to the inequality below? . . Check all that apply.. . x2 > 49. .

Marianna [84]

$x^2 \ \textgreater \ 49 \\ \\ 
x_{1,2} = \pm \sqrt{49} = \pm 7 \\ \\ 
\boxed{x \in (-\infty, ~-7)\bigcup (7,~ +\infty) }$

6 0

3 years ago

Read 2 more answers

A road perpendicular to a highway leads to a farmhouse located d miles away. An automobile traveling on this highway passes thro

pshichka [43]

Answer:

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

Step-by-step explanation:

A road is perpendicular to a highway leading to a farmhouse d miles away.

An automobile passes through the point of intersection with a constant speed $\frac{dx}{dt}$ = r mph

Let x be the distance of automobile from the point of intersection and distance between the automobile and farmhouse is 'h' miles.

Then by Pythagoras theorem,

h² = d² + x²

By taking derivative on both the sides of the equation,

$(2h)\frac{dh}{dt}=(2x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=(x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=rx$

$\frac{dh}{dt}=\frac{rx}{h}$

When automobile is 30 miles past the intersection,

For x = 30

$\frac{dh}{dt}=\frac{30r}{h}$

Since $h=\sqrt{d^{2}+(30)^{2}}$

Therefore,

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+(30)^{2}}}$

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

3 0

3 years ago

Help me please I don’t know how to do it

JulijaS [17]

Answer: The answer is 51

Step-by-step explanation:

4 0

3 years ago

Please help.

Cloud [144]

Answer:

The cups cost $3.00 and the plates cost $4.00

6 0

3 years ago