The answer would be True.
Complete Question:
Determine the number of cache sets (S), tag bits (t), set index bits (s), and block offset bits (b) for a 4096-byte cache using 32-bit memory addresses, 8-byte cache blocks and a 8-way associative design. The cache has :
Cache size = 1024 bytes, sets t = 26.8, tag bits, s = 3.2, set index bit =2
Answer:
Check below for explanations
Explanation:
Cache size = 4096 bytes = 2¹² bytes
Memory address bit = 32
Block size = 8 bytes = 2³ bytes
Cache line = (cache size)/(Block size)
Cache line = 
Cache line = 2⁹
Block offset = 3 (From 2³)
Tag = (Memory address bit - block offset - Cache line bit)
Tag = (32 - 3 - 9)
Tag = 20
Total number of sets = 2⁹ = 512
<span>C. when listing items that have an order of priority
</span>
<span>1 X 25 + 1 X 24 + 1 X 23 + 0 X 22 + 1 X 21 + 1 X 20 thus your Answer is C</span>
Answer:
Option C i.e., Interoperability is the correct option
Explanation:
Interoperability performs for computers or its components for the purpose to communicate and it is important to improve the development of the Internet of Things. It performs the communication as well as share their services between computer or its components.
It also contains challenges occurred at the time of developing and implementing the protocols by which they communicate.