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dedylja [7]
3 years ago
8

Write the definition of a method printAttitude, which has an int parameter and returns nothing. The method prints a message to s

tandard output depending on the value of its parameter. If the parameter equals 1, the method prints disagree If the parameter equals 2, the method prints no opinion If the parameter equals 3, the method prints agree In the case of other values, the method does nothing. Each message is printed on a line by itself.
Computers and Technology
1 answer:
Jlenok [28]3 years ago
6 0

Answer:

public void printAttitude(int n){

   if(n == 1){

       System.out.println("disagree");

   }

  else if(n == 2){

      System.out.println("no option");

  }

  else if(n == 3){

      System.out.println("agree");

  }

  else {

  }

}

Explanation:

The above code has been written using Java syntax. The first line denotes the method header which contains the access modifier(public), followed by the return type(void), followed by the name of the method(printAttitude). The method name is followed by a pair of parentheses in which the parameter to the method is written - in this case - an int parameter, n.

Note: When a method does not return a value. It has a return type of void as shown on the first line of the code.

In the method body, a nested if...else statement is written to test for the value of the parameter. If the parameter value of n is 1, the string "disagree" is printed to the console. Else if the parameter value of n is 2, the string "no option" is printed to the console. if the parameter value of n is 3, the string "agree" is printed to the console. For other values of n, nothing is printed. This is shown in the body of the else statement.

Hope this helps!

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Write the proghrams for the following:
belka [17]

Answer:

a)

#include <iostream>

using namespace std;

int main() {

   bool a,b,c;

   cin>>a>>b;

   if(a^b)//X-OR operator in C++.

   c=true;

   else

   c=false;

   cout<<c;

return 0;

}

b)

#include <iostream>

using namespace std;

int main() {

   bool a,b,c,d;

   cin>>a>>b>>c;

   if((a^b)^c)//X-OR operator in C++.

   d=true;

   else

   d=false;

   cout<<d;

return 0;

}

Explanation:

The above written programs are in C++.There is an operator (^) called X-OR operator in C++.It returns true if the number of 1's are odd and returns false if the number of 1's are even.

In the if statement I have user X-OR operator(^) to find the result and storing the result in another boolean variable in both the questions.

5 0
3 years ago
company gives the following discount if you purchase a large amount of supply. Units Bought Discount 10 - 19 20% 20 - 49 30% 50
ratelena [41]

Answer:

In Python:

order = int(input("Order: "))

discount = 0

if(order >= 10 and order <20):

    discount = 0.20

elif(order >= 20 and order <50):

    discount = 0.30

elif(order >= 50 and order <100):

    discount = 0.35

elif(order >= 100):

    discount = 0.40

price = order * 4.1

discount = discount * price

print("With your order of "+str(order)+" items, the total value will be $"+str(round(price,2))+" with a discount of $"+str(round(discount,2))+" for a final price of $"+str(round((price-discount),2)))

Explanation:

This prompts the user for number of orders

order = int(input("Order: "))

This initializes the discount to 0

discount = 0

For orders between 10 and 19 (inclusive)

if(order >= 10 and order <20):

-----------discount is 20%

    discount = 0.20

For orders between 20 and 49 (inclusive)

elif(order >= 20 and order <50):

-----------discount is 30%

    discount = 0.30

For orders between 50 and 99 (inclusive)

elif(order >= 50 and order <100):

-----------discount is 35%

    discount = 0.35

For orders greater than 99

elif(order >= 100):

-----------discount is 40%

    discount = 0.40

This calculates the total price

price = order * 4.1

This calculates the pre discount

discount = discount * price

This prints the report

print("With your order of "+str(order)+" items, the total value will be $"+str(round(price,2))+" with a discount of $"+str(round(discount,2))+" for a final price of $"+str(round((price-discount),2)))

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Answer:

by pressing yes

Explanation:

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