The value should be assigned to choosing two chips with the number 1 to make the game fair is 5
<h3>What is probability?</h3>
It is a branch of mathematics that deals with the occurrence of a random event.
The complete question is....
Miguel is playing a game in which a box contains four chips with numbers written on them. Two of the chips have the number 1, one chip has the number 3, and the other chip has the number 5. Miguel must choose two chips, and if both chips have the same number, he wins $2. If the two chips he chooses have different numbers, he loses $1 (–$1). a. Let X = the amount of money Miguel will receive or owe. Fill out the missing values in the table. (Hint: The total possible outcomes are six because there are four chips and you are choosing two of them.) Xi 2 –1 P(xi) b. What is Miguel’s expected value from playing the game? c. Based on the expected value in the previous step, how much money should Miguel expect to win or lose each time he plays? d. What value should be assigned to choosing two chips with the number 1 to make the game fair? Explain your answer using a complete sentence and/or an equation.
Now, for fair game the expected value =0
let the amount assigned be x
So,
1/6x-5/6=0
1/6x=5/6
x=5.
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Answer:
the nth term is -3n+13.
so if you substitute n for 63, the answer would be -176
Step-by-step explanation:
Answer:
449,100 pounds
Step-by-step explanation:
0.2% in decimal form is 0.002
0.002 (percent lost) * 450,000 (weight) = 900 (pounds lost)
450,000 - 900 = 449,100 pounds
33/2 = 16.50
16.50 - 4.50 = 12$
Simon has twelve dollars to begin with.
