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Darya [45]
3 years ago
5

On a map, the distance between Los Angeles, CA and San Francisco, CA is 51.5 cm. What is the actual distance if the map scale is

1 cm:8 mi.?
A) 4 mi
B) 4.12 mi
C) 41.2 mi
D) 412 mi
Mathematics
1 answer:
Mashutka [201]3 years ago
7 0

Answer:

shiii

Step-by-step explanation:

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Consider the sequence:<br> 1536,768, 384, 192,96, ---<br> Determine the 11th term of the sequence.
Naya [18.7K]

Answer:

1.5

Step-by-step explanation:

Note there is a common ratio between consecutive terms, that is

768 ÷ 1536 = 0.5

384 ÷ 768 = 0.5

192 ÷ 384 = 0.5

96 ÷ 192 = 0.5

This indicates that the terms form a geometric sequence with

a_{n} = a(r)^{n-1}

where a is the first term and r the common ratio

Here a = 1536 and r = 0.5, thus

a_{11} = 1536 × (0.5)^{10} = 1.5

7 0
4 years ago
Read 2 more answers
Find the domain and range
victus00 [196]

Answer:

Domain) all x

Range) 1

Step-by-step explanation:

The domain is the x values and the range is the y values

In this case anything could be x, and y can only be 1

6 0
3 years ago
Write an equation of a parabola with vertex at the origin and the given focus<br> (6,0)
Masteriza [31]

Answer:

Step-by-step explanation:

eq. of a parabola with vertex at origin and focus (a,0) is

y²=4ax

a=6

so y²=4×6×x

or y²=24 x

4 0
3 years ago
What is the equation of the axis of symmetry of a parabola if its x-intercepts are -3 and 7?
Ostrovityanka [42]
This is a parabola, meaning the equation is a quadratic, so it has 2 roots or x-intercepts, keeping in mind that vertex will lie half-way between those intercepts.

so what's the x-value halfway between -3 and 7?  yeap, you guessed it, 2.

so the axis of symmetry for this vertical parabola will be at x = 2.
7 0
3 years ago
Class A has 11 pupils and class B has 15 pupils.
Pavlova-9 [17]

Answer:

The mean score in the math test for class B=28.47

Step-by-step explanation:

<em>Step 1: Determine the total number of students in both Classes</em>

Total number of students=number in class A+number in class B

where;

number in class A=11 pupils

number in class B=15 pupils

replacing;

Total number of students=11+15=26 students

<em>Step 2: Determine total score for both classes</em>

Total score for both classes=total score for class A+total score for class B

total score for both classes=mean score for both classes×total number of students

total score for both classes=(49×26)=1,274

total score for class A=mean score for class A×total number of class A students

total score for class A=(77×11)=847

total score for class B=mean score for class B×total number of class B students

total score for class B=m×15=15 m

replacing;

1,274=847+15 m

15 m=1,274-847

15 m=427

m=427/15=28.47

The mean score in the math test for class B=28.47

7 0
3 years ago
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