<em>Use the Quadratic Formula </em>
x = -4 + 2 √11i/6, -4 - 2√11i/6
<em>Simplify solutions </em>
x = - 2 - √11i/3, - 2 + √11i/3
The mean, median, and mode of a completely normal distribution will all have the same value, represented graphically by the top of the curve. The correct option is C.
<h3>What is a normal distribution?</h3>
The mean, median, and mode of a completely normal distribution will all have the same value, represented graphically by the top of the curve. The normal distribution is often known as the bell curve because the probability density graph resembles a bell.
The option that is not true for the normal distribution is the value of the mean and the height of the density curve at its lowest are not equal.
Hence, the correct option is C.
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Each element of the matrix are multiplied by the scalar to form a matrix of
same size as the original matrix in matrix scalar multiplication.
Reasons:
The matrix <em>A</em> is presented as follows;
![A = {\left[\begin{array}{ccc}4&6&8\\6&8&10\end{array}\right]}](https://tex.z-dn.net/?f=A%20%3D%20%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%266%268%5C%5C6%268%2610%5Cend%7Barray%7D%5Cright%5D%7D)
Using the multiplication of a matrix and a scalar, we have;
![60 \cdot A = 60 \cdot \left[\begin{array}{ccc}4&6&8\\6&8&10\end{array}\right] = \left[\begin{array}{ccc}60 \times 4&60 \times 6&60 \times 8\\60 \times 6&60 \times 8&60 \times 10\end{array}\right] = \left[\begin{array}{ccc}\mathbf{240}&\mathbf{360}&\mathbf{480}\\\mathbf{360}&\mathbf{480}&\mathbf{600}\end{array}\right]](https://tex.z-dn.net/?f=60%20%5Ccdot%20A%20%3D%2060%20%5Ccdot%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%266%268%5C%5C6%268%2610%5Cend%7Barray%7D%5Cright%5D%20%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D60%20%5Ctimes%204%2660%20%5Ctimes%206%2660%20%5Ctimes%208%5C%5C60%20%5Ctimes%206%2660%20%5Ctimes%208%2660%20%5Ctimes%2010%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cmathbf%7B240%7D%26%5Cmathbf%7B360%7D%26%5Cmathbf%7B480%7D%5C%5C%5Cmathbf%7B360%7D%26%5Cmathbf%7B480%7D%26%5Cmathbf%7B600%7D%5Cend%7Barray%7D%5Cright%5D)
Therefore;
![60 \cdot A = \left[\begin{array}{ccc}240\4&360&480\\360&480&600\end{array}\right]](https://tex.z-dn.net/?f=60%20%5Ccdot%20A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D240%5C4%26360%26480%5C%5C360%26480%26600%5Cend%7Barray%7D%5Cright%5D)
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Answer:
The median is 17 and the mode is 19
Step-by-step explanation: