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Leviafan [203]
3 years ago
5

How many different strings of length 12 containing exactly five a's can be chosen over the following alphabets? (a) The alphabet

{a, b} keyboard_arrow_down Solution (b) The alphabet {a, b, c}
Mathematics
1 answer:
N76 [4]3 years ago
7 0

Answer:

Part (A) The required ways are 792.

Part (B) The required ways are 101376.

Step-by-step explanation:

Consider the provided information.

Part (A) The alphabet {a, b}

The length of strings is 12 that containing exactly five a's.

The number of ways are: \frac{12!}{5!7!}

After filling "a" we have now 7 places.

For 7 places we have "a" and "b" alphabet but we already select a's so now the remaining place have to fill by "b" only.

Thus, the required ways are: \frac{12!}{5!7!}\times 1=792

Part (B) The alphabet {a, b, c}

We have selected five a's now we have now 7 places.

For 7 places we have "b" and "c".

Thus, there are 2 choices for each 7 place that is 2^7

Therefore the total number of ways are: 792\times 2^7=101376

Thus, the required ways are 101376.

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3 years ago
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Stanley has $18 to spend on packs of trading cards that cost $1.50 each. The inequality 18≥1.5p represents the number of packs p
V125BC [204]

Answer:

Numbers of packs p is 12

Step-by-step explanation:

Data :

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krok68 [10]
There are many systems of equation that will satisfy the requirement for Part A.
an example is y≤(1/4)x-3 and y≥(-1/2)x-6
y≥(-1/2)x-6 goes through the point (0,-6) and (-2, -5), the shaded area is above the line. all the points fall in the shaded area, but
y≤(1/4)x-3 goes through the points (0,-3) and (4,-2), the shaded area is below the line, only A and E are in the shaded area. 
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For y≥(-1/2)x-6: -4≥(-1/2)(-3)-6
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8 0
2 years ago
A car is moving with an initial velocity of 10 mph accelerates at the rate of a(t)=2.5t mph per second for 5 seconds. How fast i
Rom4ik [11]

Answer:

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Step-by-step explanation:

In this question, we are asked to calculate the speed of a moving car which started moving at an initial velocity for a specific period of time.

To calculate this, we use one of the basic equations of motion;

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Hence a here would be 2.5 * 5 = 12.5

Now, let’s put these values in the equation

v = 10 + 12.5

v = 22.5 mph

3 0
3 years ago
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