Hello here is a solution :
<span>x² − 8x − 4 = 0.
</span><span>quadratic equation ax²+bx+c = 0 when : a=1 and b= -8 and c = -4
discriminant : d = b²-4ac d= (-8)²-4(1)(-4) =64+16 =70
x= (-b-rot(d))/2a </span>x'= (-b+rot(d))/2a .......conrinu
Answer:
210 cm³
Step-by-step explanation:
The area of the triangular side is base*half height, which is 7*3=21.
To get the volume, multiply by the depth: 21*10 = 210 cm³
Answer:
Numbers of packs p is 12
Step-by-step explanation:
Data :
Money = $18
Price of a card = $1.5
Equation : 18 ≥ 1.5p
Solve the equation for p
18/1.5 ≥ p
12 ≥ p
There are many systems of equation that will satisfy the requirement for Part A.
an example is y≤(1/4)x-3 and y≥(-1/2)x-6
y≥(-1/2)x-6 goes through the point (0,-6) and (-2, -5), the shaded area is above the line. all the points fall in the shaded area, but
y≤(1/4)x-3 goes through the points (0,-3) and (4,-2), the shaded area is below the line, only A and E are in the shaded area.
only A and E satisfy both inequality, in the overlapping shaded area.
Part B. to verify, put the coordinates of A (-3,-4) and E(5,-4) in both inequalities to see if they will make the inequalities true.
for y≤(1/4)x-3: -4≤(1/4)(-3)-3
-4≤-3&3/4 This is valid.
For y≥(-1/2)x-6: -4≥(-1/2)(-3)-6
-4≥-4&1/3 this is valid as well. So Yes, A satisfies both inequalities.
Do the same for point E (5,-4)
Part C: the line y<-2x+4 is a dotted line going through (0,4) and (-2,0)
the shaded area is below the line
farms A, B, and D are in this shaded area.
Answer:
The car is going up at a speed of 22.5 mph
Step-by-step explanation:
In this question, we are asked to calculate the speed of a moving car which started moving at an initial velocity for a specific period of time.
To calculate this, we use one of the basic equations of motion;
v = u + at
Where v is the final velocity, u is the initial velocity and t is the time
From the question, we can identify the parameters as follows;
v = ?
u = 10mph
a = 2.5t mph per second for 5 seconds.
Hence a here would be 2.5 * 5 = 12.5
Now, let’s put these values in the equation
v = 10 + 12.5
v = 22.5 mph