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OverLord2011 [107]
3 years ago
5

Construct a circle through points X, Y, and Z.

Mathematics
1 answer:
Olin [163]3 years ago
7 0
How does that move? Does it stay out or can it move? If it can you can just create one with the outer line touching it..? I don’t know this :’)
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Mrac [35]
Sorry do know that one !!☹️
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3 years ago
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The volume of a rectangular prism is 2x^3+9x^2-8x-36 with height x + 2. Using synthetic division, what is the area of the base?
navik [9.2K]

Answer:

Area of the base = 2x^2+5x-18

Step-by-step explanation:

We know that volume of rectangular prism = (Area of base) x (Height)

or [Area of base] = [Volume]/[Height]

So basically we need to divide given area by given height to find the answer.

given height is (x+2) that means (x+2) must be factor of volume equation

or x=-2 must be root of volume equation so write down coefficients of volume equation then we divide by -2 as shown in attached picture.

Last digit on the right is always remainder.

Remaining coefficients {2, 5, -18} will give the area equation: 2x^2+5x-18

Hence final answer is:

Area of the base = 2x^2+5x-18


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3 years ago
Which of the following statements is the contrapositive of "If I have money, then I spend it"?
Vika [28.1K]
Im looking towards B
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3 years ago
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Which represents the reflection of f(x)=√x over the y-axis?
ololo11 [35]

We are looking for the graph of y=\sqrt{-x}. which is shown in the attached image.

8 0
2 years ago
Directions: State whether or not (3, -2) is a solution to the following systems.
andrew11 [14]

(3, -2) is a solution to the system of equations x - 2y = 7 and 2x + 3y = 0, (3, -2) is not a solution to the system of equations  -x - y = -5 and 3x - 4y = 17 and (3, -2) is not a solution to the system of equations x + y = 1 and x - y = 6

<h3>How to determine the whether or not (3, -2) is a solution to the following systems?</h3>

The systems of equations are given as:

1. x - 2y = 7 and 2x + 3y = 0

2. -x - y = -5 and 3x - 4y = 17

3. x + y = 1 and x - y = 6

Next, we substitute (3, -2) for (x, y) in the system of equations.

So, we have:

<u>1. x - 2y = 7 and 2x + 3y = 0</u>

3 - 2 * -2 = 7 and 2 * 3 + 3 * -2 = 0

Evaluate

7 = 7 and 0 = 0

The above equation is true

Hence, (3, -2) is a solution to the system of equations x - 2y = 7 and 2x + 3y = 0

<u>2.- x - y = -5 and 3x - 4y = 17</u>

-3 + 2 = -5 and 3 * 3 + 4 * 2 = 17

Evaluate

- 1 = - 5 and 1 7 = 1 7

The above equation is false

Hence, (3, -2) is not a solution to the system of equations  -x - y = -5 and 3x - 4y = 17

<u>3. x + y = 1 and x - y = 6</u>

3 - 2 = 1 and 3 + 2 = 6

Evaluate

1 = 1 and 5 = 6

The above equation is false

Hence, (3, -2) is not a solution to the system of equations x + y = 1 and x - y = 6

Read more about system of equations at:

brainly.com/question/13729904

#SPJ1

8 0
2 years ago
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