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lana66690 [7]
3 years ago
14

Arrange the equations in the correct sequence to rewrite the formula for displacement, d = vt—1/2at^2 to find a. In the formula,

d is
displacement, v is final velocity, a is acceleration, and t is time.

Mathematics
1 answer:
Murljashka [212]3 years ago
6 0

Answer:

a = \frac{2(vt-d)}{t^{2} }

Step-by-step explanation:

Given the formula for calculating the displacement of a body as shown below;

d = vt - \frac{1}{2} at^{2}

d = displacement

v = final velocity

a = acceleration

t = time

To make the acceleration a the subject of the formula, the followin steps must be taken;

Step 1: Subtract vt from both sides of the equation

d-vt = vt-vt-\frac{1}{2}at^{2} \\ d-vt = -\frac{1}{2}at^{2}\\2(d-vt) = -at^{2}

Step 2: Divide both sides by t²

\frac{2(d-vt)}{t^{2} } = \frac{-at^{2} }{t^{2} } \\a = \frac{-2(d-vt)}{t^{2} }

a = \frac{2(vt-d)}{t^{2} }

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Answer:

C

Step-by-step explanation:

the angle measures of triangles must add up to 180 degrees. Since we are only given two angles, we can assume that all of the answers that add up to be below 180 degrees fulfill this requirement with the third angle. However, answer choice C adds up to 190 degrees on the first two angle, which means that no matter how low the third angle is, it will never add up to 180 degrees.

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Select correct answer
Sergio [31]

Answer:

The values of p in the equation are 0 and 6

Step-by-step explanation:

First, you have to make the denominators the same. to do that, first factor 2p^2-7p-4 = \left(2p+1\right)\left(p-4\right)2p

2

−7p−4=(2p+1)(p−4)

So then the equation looks like:

\frac{p}{2p+1}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{5}{p-4}

2p+1

p

−

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2p

2

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=−

p−4

5

To make the denominators equal, multiply 2p+1 with p-4 and p-4 with 2p+1:

\frac{p^2-4p}{(2p+1)(p-4)}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{10p+5}{(p-4)(2p+1)}

(2p+1)(p−4)

p

2

−4p

−

(2p+1)(p−4)

2p

2

+5

=−

(p−4)(2p+1)

10p+5

Since, this has an equal sign we 'get rid of' or 'forget' the denominator and only solve the numerator.

(p^2-4p)-(2p^2+5)=-(10p+5)(p

2

−4p)−(2p

2

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Now, solve like a normal equation. Solve (p^2-4p)-(2p^2+5)(p

2

−4p)−(2p

2

+5) first:

(p^2-4p)-(2p^2+5)=-p^2-4p-5(p

2

−4p)−(2p

2

+5)=−p

2

−4p−5

-p^2-4p-5=-10p+5−p

2

−4p−5=−10p+5

Combine like terms:

-p^2-4p+0=-10p−p

2

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Factor:

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