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lana66690 [7]
3 years ago
14

Arrange the equations in the correct sequence to rewrite the formula for displacement, d = vt—1/2at^2 to find a. In the formula,

d is
displacement, v is final velocity, a is acceleration, and t is time.

Mathematics
1 answer:
Murljashka [212]3 years ago
6 0

Answer:

a = \frac{2(vt-d)}{t^{2} }

Step-by-step explanation:

Given the formula for calculating the displacement of a body as shown below;

d = vt - \frac{1}{2} at^{2}

d = displacement

v = final velocity

a = acceleration

t = time

To make the acceleration a the subject of the formula, the followin steps must be taken;

Step 1: Subtract vt from both sides of the equation

d-vt = vt-vt-\frac{1}{2}at^{2} \\ d-vt = -\frac{1}{2}at^{2}\\2(d-vt) = -at^{2}

Step 2: Divide both sides by t²

\frac{2(d-vt)}{t^{2} } = \frac{-at^{2} }{t^{2} } \\a = \frac{-2(d-vt)}{t^{2} }

a = \frac{2(vt-d)}{t^{2} }

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The  average temperature  is T_{a} = 81.95^oC

Step-by-step explanation:

From the question we are told that

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Now the average temperature during the first 22 minutes i.e fro 0 \to  22minutes is mathematically evaluated as

              T_{a} =  \frac{1}{22-0}  \int\limits^{22}_{0} {25 +72 e^{[-\frac{t}{45} ]}} \, dx

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             T_{a} = \frac{1}{22} [25 t  - 3240e^{[-\frac{t}{45} ]} ] \left | 45} \atop {{0}} \right.

              T_{a} = \frac{1}{22} [25 (22)  - 3240e^{[-\frac{22}{45} ]}   - (- 3240e^{0} )]

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7x = - 14

7x/7 = - 14/7     divide both sides by 7

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