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MAXImum [283]
3 years ago
11

50 POINTS!!!

Mathematics
1 answer:
Goryan [66]3 years ago
3 0

9514 1404 393

Answer:

  • f(x) = x
  • g(x) = -2x+1
  • f(x) -(-g(x)) = -x+1
  • f(x) +g(x) = -x+1
  • f(x)-(-g(x)) = (f+g)(x) is true for all functions f and g, linear or not

Step-by-step explanation:

We can define a couple of linear functions as ...

  f(x) = x

  g(x) = -2x+1

Then the reflected function -g(x) is ...

  -g(x) = -(-2x +1) = 2x -1

And the difference from f(x) is ...

  f(x) -(-g(x)) = x -(2x -1) = -x +1 . . . . f(x) -(-g(x))

We want to compare that to the sum of the functions:

  f(x) +g(x) = x +(-2x +1) = -x +1 . . . . f(x) +g(x)

The two versions of the function expression have the same value.

These results are <em>a property of addition</em>, so do not depend on the nature of f(x) or g(x). They will hold for every function.

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Artemon [7]
The model size would be 8.82 feet I think
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3 years ago
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Which expression is equivalent to 36^-1/2
inn [45]
ANSWER


( {36})^{ (-  \frac{1}{2}) }  =  \frac{1}{6}


EXPLANATION



The given expression is


{36}^{( -  \frac{1}{2} )}
This is having a negative index. We must first of all change to a positive index.


Recall that,



{a}^{ - m}  =  \frac{1}{ {a}^{m} }

We apply this law of exponents to get,



{36}^{( -  \frac{1}{2} )}  =  \frac{1}{ {36}^{(  \frac{1}{2} )} }

We cab rewrite the given expression to obtain;



{36}^{( -  \frac{1}{2} )}  =  \frac{1}{  \sqrt{36}  }

This will simplify to give us,


{36}^{( -  \frac{1}{2} )}  =  \frac{1}{  6 }


6 0
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Can someone answer this plssss
Tpy6a [65]

Answer:

AB : Y= 4  CB: Y= -1

Step-by-step explanation:

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3 years ago
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SIZIF [17.4K]
0.10d + 0.25q = 3.55
q = d + 3

0.10d + 0.25(d + 3) = 3.55
0.10d + 0.25d + 0.75 = 3.55
0.10d + 0.25d = 3.55 - 0.75
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d = 2.80/0.35
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q = d + 3
q = 8 + 3
q = 11 <=== 11 quarters
3 0
3 years ago
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