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bulgar [2K]
3 years ago
13

Find the area of a circle with a circumfrence of 53.41 inches

Mathematics
2 answers:
netineya [11]3 years ago
7 0
About 224.7 I think. I hope this helps
tankabanditka [31]3 years ago
4 0
The area would be 227.00493145892 inches squared, but I would round it to 227 inches squared
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The area of the triangle
hram777 [196]
Area=1/2 times base times height
base=4
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area=6 square units
8 0
3 years ago
10 POINTS AND BRAINLIEST<br> URGENT MATH QUESTION SEE PICTURE
Lostsunrise [7]

The point-slope form:

y-y_1=m(x-x_1)

m - slope

(x_1,\ y_1) - point

We have the point (3,\ -2)\to x_1=3,\ y_1=-2 and the slope m=\dfrac{2}{3}

Substitute:

y-(-2)=\dfrac{2}{3}(x-3)\\\\\boxed{y+2=\dfrac{2}{3}(x-3)}

5 0
3 years ago
Which number in the monomial 125x^18y^3z^25 needs to be changed to make it a perfect cube
Oksana_A [137]

Hi,

You just have to change z^25 to z^24 or z^27.

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4 0
3 years ago
Read 2 more answers
A financial advisor is analyzing a family's estate plan. The amount of money that the family has invested in different real esta
Pachacha [2.7K]

Answer:

The amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.

Step-by-step explanation:

Let the random variable <em>X</em> represent the amount of money that the family has invested in different real estate properties.

The random variable <em>X</em> follows a Normal distribution with parameters <em>μ</em> = $225,000 and <em>σ</em> = $50,000.

It is provided that the family has invested in <em>n</em> = 10 different real estate properties.

Then the mean and standard deviation of amount of money that the family has invested in these 10 different real estate properties is:

\mu_{\bar x}=\mu=\$225,000\\\\\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{50000}{\sqrt{10}}=15811.39

Now the lowest 80% of the amount invested can be represented as follows:

P(\bar X

The value of <em>z</em> is 0.84.

*Use a <em>z</em>-table.

Compute the value of the mean amount invested as follows:

\bar x=\mu_{\bar x}+z\cdot \sigma_{\bar x}

   =225000+(0.84\times 15811.39)\\\\=225000+13281.5676\\\\=238281.5676\\\\\approx 238281.57

Thus, the amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.

6 0
3 years ago
What is the answer for 0.025×10=
Mashutka [201]
The answer would be 0.25... when multiplying by 10, shift the decimal place one to the right.
8 0
3 years ago
Read 2 more answers
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