An equation states two things are equal to the other one side is equal to the other side. a)4y+8 b)4y+8=16
1 answer:
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Given:
l = length of the rectangle
w = width of the rectangle
P = 4 ft, constant perimeter
Because the given perimeter is constant,
2(w + l) = 4
w + l = 2
w = 2 - l (1)
Part A.
The area is
A = w*l
= (2 - l)*l
A = 2l - l²
This is a quadratic function or a parabola.
Part B.
Write the parabola in standard form.
A = -[l² - 2l]
= -[ (l -1)² - 1]
= -(l -1)² + 1
This is a parabola with vertex at (1, 1). Because the leading coefficient is negative the curve is downward, as shown below.
The maximum value occurs at the vertex, so the maximum value of A = 1.
From equation (1), obtain
w = 2 - l = 2 - 1 = 1.
The maximum value of the area occurs when w=1 and l=1 (a square).
Answer:
The area is maximum when l=1 and w=1.
The geometric argument is based on the vertex of the parabola denoting maximum area.
l = length of the rectangle
w = width of the rectangle
P = 4 ft, constant perimeter
Because the given perimeter is constant,
2(w + l) = 4
w + l = 2
w = 2 - l (1)
Part A.
The area is
A = w*l
= (2 - l)*l
A = 2l - l²
This is a quadratic function or a parabola.
Part B.
Write the parabola in standard form.
A = -[l² - 2l]
= -[ (l -1)² - 1]
= -(l -1)² + 1
This is a parabola with vertex at (1, 1). Because the leading coefficient is negative the curve is downward, as shown below.
The maximum value occurs at the vertex, so the maximum value of A = 1.
From equation (1), obtain
w = 2 - l = 2 - 1 = 1.
The maximum value of the area occurs when w=1 and l=1 (a square).
Answer:
The area is maximum when l=1 and w=1.
The geometric argument is based on the vertex of the parabola denoting maximum area.
Answer:
1.2%
Step-by-step explanation:
We are given that the students receive different versions of the math namely A, B, C and D.
So, the probability that a student receives version A = .
Thus, the probability that the student does not receive version A = =
.
So, the possibilities that at-least 3 out of 5 students receive version A are,
1) 3 receives version A and 2 does not receive version A
2) 4 receives version A and 1 does not receive version A
3) All 5 students receive version A
Then the probability that at-least 3 out of 5 students receive version A is given by,
+
+
=
=
=
=
= 0.01171875 × 1.0625
= 0.01245
Thus, the probability that at least 3 out of 5 students receive version A is 0.0124
So, in percent the probability is 0.0124 × 100 = 1.24%
To the nearest tenth, the required probability is 1.2%.
Answer:
96 sq. cm.
Step-by-step explanation:
A "kite" has 2 diagonals, which are the "width" and "height" of the kite.
Using diagonals, the area of a kite is given by
Where
A is the area
p,q are the width and height, respectively
From the problem given, p is 12 and q is 16, so the area is:
Thus, the area is 96 sq. cm