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3 years ago

Can u pls help i have a few mins left

Mathematics

2 answers:

BartSMP [9]3 years ago

6 0

Answer:

Step-by-step explanation:

Assoli18 [71]3 years ago

3 0

1/2. Because the coin only has two sides, therefore it can only land on either side. The die has 6 sides, so it’s 1/6 because it can land on one of six sides.

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A cement block is in the shape of a rectangular prism that measures 4.5 feet by 7.25 feet by 6.5 feet. The entire block must be

irakobra [83]

I am pretty sure that if you are looking for perimeter there should only be two sets of numbers but if you are looking for area than the answer would be 212.0625

6 0

3 years ago

Read 2 more answers

PLLSSS REALLY URGENT If g(x)=3x+4, determine n that g(-3)=g^-1(n).

grigory [225]

Answer:

we have:

g(-3) = 3.(-3) + 4 = -5

$g {}^{ - 1} (n) = \frac{1}{3n + 4}$

because

$g( - 3) = g {}^{ - 1} (n)$

$- 5 = \frac{1}{3n + 4} \\ \\ < = > - 5(3n + 4) = 1 \\ \\ < = > - 15n - 20 = 1 \\ \\ < = > n = \frac{ - 21}{15} \\ \\ < = > n = \frac{ - 7}{5}$

5 0

2 years ago

Suppose a rectangular pasture is to be constructed using 1 2 linear mile of fencing. The pasture will have one divider parallel

timama [110]

Answer:

$\displaystyle A=\frac{1}{192}$

Step-by-step explanation:

Maximization With Derivatives

Given a function of one variable A(x), we can find the maximum or minimum value of A by using the derivatives criterion. If A'(x)=0, then A has a probable maximum or minimum value.

We need to find a function for the area of the pasture. Let's assume the dimensions of the pasture are x and y, and one divider goes parallel to the sides named y, and two dividers go parallel to x.

The two divisions parallel to x have lengths y, thus the fencing will take 4x. The three dividers parallel to y have lengths x, thus the fencing will take 3y.

The amount of fence needed to enclose the external and the internal divisions is

$P=4x+3y$

We know the total fencing is 1/2 miles long, thus

$\displaystyle 4x+3y=\frac{1}{2}$

Solving for x

$\displaystyle x=\frac{\frac{1}{2}-3y}{4}$

The total area of the pasture is

$A=x.y$

Substituting x

$\displaystyle A=\frac{\frac{1}{2}-3y}{4}.y$

$\displaystyle A=\frac{\frac{1}{2}y-3y^2}{4}$

Differentiating with respect to y

$\displaystyle A'=\frac{\frac{1}{2}-6y}{4}$

Equate to 0

$\displaystyle \frac{\frac{1}{2}-6y}{4}=0$

Solving for y

$\displaystyle y=\frac{1}{12}$

And also

$\displaystyle x=\frac{\frac{1}{2}-3\cdot \frac{1}{12}}{4}=\frac{1}{16}$

Compute the second derivative

$\displaystyle A''=-\frac{3}{2}.$

Since it's always negative, the point is a maximum

Thus, the maximum area is

$\displaystyle A=\frac{1}{12}\cdot \frac{1}{16}=\frac{1}{192}$

6 0

3 years ago

Find the product and write in lowest term. Give me an integer or simplified fraction. 7/54×27/35

wariber [46]

The product of given expression is $\frac{1}{15} \text{ or } 0.0667$

Solution:

Given that we have to find the product and write it in lowest term

Given expression is:

$\frac{7}{54} \times \frac{27}{35}$

Let us first find common factors of numerator and denominator so, thet simplification becomes easier

$54 = 27 \times 3\\\\35 = 7 \times 5$

Substituting these in above expression, we get

$\rightarrow \frac{7}{27 \times 3} \times \frac{27}{7 \times 5}$

Cancel the common factors in numerator and denominator

$\rightarrow \frac{1}{15}$

In decimal form, we get

$\rightarrow \frac{1}{15} = 0.0667$

Thus the product of given expression is $\frac{1}{15} \text{ or } 0.0667$

4 0

3 years ago

-20y + 15 = 2 - 16y + 11

shtirl [24]

In order to answer this, we will first need to combine like terms on each side. on the left, you can leave them alone. however on the right, we will need to combine 2 and 11. this is 13. the right side becomes 13-16y. after that, we can add 20y to both sides. that equals 15=13+4y now we can subtract 13 from both sides. 2=4y. then we divide by 4 on both sides to find y. y=.5

7 0

3 years ago