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3 years ago

la razon entre los pesos de juan y su padre es 2:5, si sus pesos suman 105 kg, ¿cuanto pesa juan y cuanto pesa su papa?

Mathematics

1 answer:

Afina-wow [57]3 years ago

8 0

Is Kevin Nash
La u si

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An automotive part manufacturer regularly makes shipments of 400 parts to merks auto repair. On average, 14 of the 400 parts are

Radda [10]

Answer:

no matter how many parts are in the shipment, 3.5% of the parts will be defective.

hope this helped, if so hit that thanks button ;D

Step-by-step explanation:

4 0

2 years ago

Can someone simplify this expression? 14y – 5(3 – 2y) and explain how you got it.

Paraphin [41]

You first expand the brackets so
14y-15-10y
then you put the like terms together so you do 14y-10y= 4y
4y-15 which is the answer

4 0

2 years ago

Read 2 more answers

What is the answer to number 1 question?

never [62]

I do not know the answer

8 0

3 years ago

A veterinarian wants to know if pit bulls or golden retrievers have a higher incidence of tooth decay at the age of three. The v

BigorU [14]

Answer: B) [-0.0332,0.1332]

Step-by-step explanation: Confidence Interval is an interval where we can be a percentage sure the true mean is.

The confidence interval for a difference in population proportion is calculated following these steps:

First, let's find population proportion for each population:

$p_{1}=\frac{30}{120}=0.25$

$p_{2}=\frac{32}{160}=0.2$

Second, calculate standard deviation for each proportion:

$\sigma_{1}=\sqrt{\frac{0.25(0.75)}{120} } = 0.0395$

$\sigma_{2}=\sqrt{\frac{0.2(0.8)}{160} } = 0.0316$

Now, we calculate standard error for difference:

$SE=\sqrt{\sigma_{1}^{2}+\sigma_{2}^{2}}$

$SE=\sqrt{0.0395^{2}+0.0316^{2}}$

SE = 0.0505

The z-score for a 90% CI is 1.645.

Then, confidence interval is

$p_{1}-p_{2}$ ± z-score.SE

$0.25-0.2$ ± $1.645(0.0505)$

0.05 ± 0.0831

The limits of this interval are:

inferior: 0.05 - 0.0831 = $-0.0332$

superior: 0.05 + 0.0831 = 0.1332

The 90% confidence interval for the difference in the population proportion of pit pulls and golden retrievers is $[-0.0332,0.1332]$ .

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=%2832%29%5E%7B1%2F5%7D" id="TexFormula1" title="(32)^{1/5}" alt="(32)^{1/5}" align="absmiddle"

lorasvet [3.4K]

Answer:

Step-by-step explanation:

${32}^{ \frac{1}{5} }$

$= \sqrt[5]{32}$

$= \sqrt[5]{2 \times 2 \times 2 \times 2 \times 2}$

= 2 (Ans)

4 0

2 years ago