Using <span>Compound interest formula:
</span>
<span><span>The exponential function for calculating the amount of money after <span>t <span>years, <span>A<span>(<span>t<span>), where<span> P <span>is the initial amount or principal, the annual interest rate is <span>r <span>and the number of times<span> interest is compounded per year is n, is given by
</span></span></span></span></span></span></span></span></span></span></span></span>

</span><span>from the given information:
p = 2,310 , r = 0.035 ,
</span><span>compounded daily ⇒⇒⇒ n =365
To calculate the time : </span>deposited April 12 and withdrawn July 5<span>
t = 2 months and 23 days = 83 days = 83/365 years
∴ n t = 365 * 83/365 = 83
Amount = </span>
<span>

= 2,328.46
</span>The interest earned = <span><span>2,328.6458</span> - 2,310 = 18.46
</span>
Answer:
3456
Step-by-step explanation:
times 36cm*16cm*6cm
Answer:
About 5.93412 radians.
Step-by-step explanation:
To calculate it you would multiply 340 by π/180 because if graphed, 340 degrees is located in the first quadrant.
I hope this helps! :)
Answer:

Step-by-step explanation:
A(t) is the amount of salt in the tank at time t.
dA / dt = rate of salt flowing into the tank - rate of salt going out of the tank
dA / dt = (1 g/L)*(5 L/min) - (A(t)/250 g/L) * (5L/min)
dA / dt = 5 g/min - (A(t) / 50) g/min
![\frac{dA}{dt}+\frac{A(t)}{50} = 5\\\\The\ integrating\ factor(IF)= e^{\int\limits \frac{1}{50}dt }=e^{\frac{t}{50} }\\\\Multiplying\ through\ by\ the\ I.F:\\\\\frac{dA}{dt}*e^{\frac{t}{50} }+\frac{A(t)}{50}*e^{\frac{t}{50} } = 5*e^{\frac{t}{50} }\\\\Integrating \ both \ sides:\\\\\int\limits[ \frac{dA}{dt}*e^{\frac{t}{50} }+\frac{A(t)}{50}*e^{\frac{t}{50} }] dt=\int\limits 5e^{\frac{t}{50} } dt\\\\A(t)e^{\frac{t}{50} } =\int\limits 5e^{\frac{t}{50} } dt\\\\](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdt%7D%2B%5Cfrac%7BA%28t%29%7D%7B50%7D%20%3D%205%5C%5C%5C%5CThe%5C%20integrating%5C%20factor%28IF%29%3D%20e%5E%7B%5Cint%5Climits%20%5Cfrac%7B1%7D%7B50%7Ddt%20%7D%3De%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%5C%5C%5C%5CMultiplying%5C%20through%5C%20by%5C%20the%5C%20I.F%3A%5C%5C%5C%5C%5Cfrac%7BdA%7D%7Bdt%7D%2Ae%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%2B%5Cfrac%7BA%28t%29%7D%7B50%7D%2Ae%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%20%3D%205%2Ae%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%5C%5C%5C%5CIntegrating%20%5C%20both%20%5C%20sides%3A%5C%5C%5C%5C%5Cint%5Climits%5B%20%20%5Cfrac%7BdA%7D%7Bdt%7D%2Ae%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%2B%5Cfrac%7BA%28t%29%7D%7B50%7D%2Ae%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%5D%20dt%3D%5Cint%5Climits%20%205e%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%20dt%5C%5C%5C%5CA%28t%29e%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%20%3D%5Cint%5Climits%20%205e%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%20dt%5C%5C%5C%5C)

Answer:
12 n 4−36 n 2+27 ... 12n4 - 36n2 + 27 = 3 • (4n4 - 12n2 + 9) ... splitting the middle term using the two factors found in step 2 above, -6 and -6
Step-by-step explanation:
hope this helps