Multiply length time width, and make sure you square your answer!
We can first add up the cards so we know how many we have in all:
16 + 16 + 18 = 50 cards
We can do this a little bit easier if we get the "16"-cards in one number total.
16 + 16 = 32
= 32 x 2 =
50 x 2
= 64 : 2 = 32 %
100
We did just divide the % of two types cards on 2, so we get the %-chance of 1 type card.
I am not quite sure, but I think that 32 % is the correct answer.
The general equation for a circle,
, falls out of the Pythagorean Theorem, which states that the square of the hypotenuse of a right triangle is always equal to the sum of the squares of its legs (you might have seen this fact written like
, where <em>a </em>and <em>b</em> are the legs of a right triangle and <em>c </em>is its hypotenuse. When we fix <em /><em>c</em> in place and let <em>a </em>and <em>b </em>vary (in a sense, at least; their values are still dependent on <em>c</em>), the shape swept out by all of those possible triangles is a circle - a shape defined by having all of its points equidistant from some center.
How do we modify this equation to shift the circle and change its radius, then? Well, if we want to change the radius, we simply have to change the hypotenuse of the triangle that's sweeping out the circle in the first place. The default for a circle is 1, but we're looking for a radius of 6, so our equation, in line with Pythagorus's, would look like
, or
.
Shifting the center of the circle is a bit of a longer story, but - at first counterintuitively - you can move a circle's center to the point (a,b) by altering the x and y portions of the equation to read:
Question:
What are the square roots of 36/100?
Answer
A. −6/10 and 6/10
Answer: The velocity of the ball is 108.8 ft/s downwards.
Step-by-step explanation:
When the ball is dropped, the only force acting on the ball will be the gravitational force. Then the acceleration of the ball will be the gravitational acceleration, that is something like:
g = 32 ft/s^2
To get the velocity equation we need to integrate over time, to get:
v(t) = (32ft/s^2)*t + v0
where v0 is the initial velocity of the ball. (t = 0s is when the ball is dropped)
Because it is dropped, the initial velocity is equal to zero, then we get:
v(t) = (32ft/s^2)*t
Which is the same equation that we can see in the hint.
Now we want to find the velocity 3.4 seconds after the ball is dropped, then we just replace t by 3.4s, then we get:
v(3.4s) = (32ft/s^2)*3.4s = 108.8 ft/s
The velocity of the ball is 108.8 ft/s downwards.