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Zepler [3.9K]
3 years ago
7

Please factorise the equations in the doc bellow ASAP. please show full working

Mathematics
2 answers:
ad-work [718]3 years ago
8 0

Answer:

b. x² + 8x + 12 =

1. use the factoring X (see attachment)

2. 6 x 2 = 12; 6 + 2 = 12

3. (x + 6)(x + 2) = 0

4. x = -6, -2

c. x² + 13x + 12 =

1. 12 x 1 = 12; 12 + 1 = 13

2. (x + 12)(x + 1) = 0

3. x = -12, -1

c. x² + x - 12 =

1. 4 · (-3) = -12; 4 - 3 = 1

2. (x +4)(x - 3) = 0

3. x = -4, 3

f. x² + 15x + 36 =

1. 12 x 3 = 36; 12 + 3 = 15

2. (x + 12)(x + 3) = 0

3. x = -12, -3

hope this helps :)

Naddik [55]3 years ago
8 0

Answer:

b) - (x + 2)(x + 6)

c) - (x + 12)(x + 1)

c) - (x - 3)(x + 4)

f) - (x + 12)(x + 3)

Step-by-step explanation:

Well to factor the given info we need to find the factors.

b)

x^2 + 8x + 12

So 6*2 = 12

6x + 2x = 8x

x*x = x^2

Factored - (x + 2)(x + 6)

c)

x^2 + 13x + 12

Well x*x = x^2

and 12*1 = 12

12x + x = 13x

Factored - (x + 12)(x + 1)

The second c)

x^2 + x - 12

Well x*x = x^2

-3*4 = -12

-3x + 4x = x

Factored - (x - 3)(x + 4)

f)

x^2 + 15x + 36

So x*x = x^2

12*3 = 36

12x + 3x = 15x

Factored - (x + 12)(x + 3)

<em />

<em>Thus,</em>

<em>everything factored is (x + 2)(x + 6) , (x + 12)(x + 1) , (x - 3)(x + 4) , </em>

<em>(x + 12)(x + 3).</em>

<em />

<em>Hope this helps :)</em>

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babunello [35]

Using the given linear function, the formula underestimates the median weekly earnings in 2013 by $3.

<h3>What is the linear function for the estimate?</h3>

The function that estimates the median weekly earnings n years after 1980 is given by:

W = 13n + 231.

2013 is 2013-1980 = 33 years after 2000, hence the estimate is given by:

W = 13 x 33 + 231 = 660.

Since 657 < 660, the formula underestimates the median weekly earnings in 2013 by $3.

More can be learned about linear functions at brainly.com/question/24808124

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5 0
2 years ago
The breaking strengths of cables produced by a certain manufacturer have a mean, , of pounds, and a standard deviation of pounds
olchik [2.2K]

The question is incomplete. The complete question is :

The breaking strengths of cables produced by a certain manufacturer have a mean of 1900 pounds, and a standard deviation of 65 pounds. It is claimed that an improvement in the manufacturing process has increased the mean breaking strength. To evaluate this claim, 150 newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be 1902 pounds. Assume that the population is normally distributed. Can we support, at the 0.01 level of significance, the claim that the mean breaking strength has increased?

Solution :

Given data :

Mean, μ = 1900

Standard deviation, σ = 65

Sample size, n = 150

Sample mean, $\overline x$ = 1902

Level of significance = 0.01

The hypothesis are :

$H_0 : \mu = 1900$

$H_1 : \mu > 1900$

Test statics :

We use the z test as the sample size is large and we know the population standard deviation.

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$z=\frac{2}{5.30723}$

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Finding the p-value:

P-value = P(Z > z)

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From the z table. we get

P(Z < 0.38) = 0.6480

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P-value = 1 - P(Z < 0.38)

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Decision :

If the p value is less than 0.01, then we reject the H_0, otherwise we fail to reject  H_0.

Since the value of p = 0.3520 > 0.01, the level of significance, then we fail to reject  H_0.

Conclusion :

At a significance level of 0.01, we have no sufficient evidence to support that the mean breaking strength has increased.

4 0
3 years ago
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bazaltina [42]

Answer:

Area of PSTK = 50

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△SPK:

SK = 13, PK = 12

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3 years ago
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butalik [34]
Did show all work for ya

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