Chris and Jim must replace a <em>total</em> quantity of 17 tyres.
<h3>What is the minimum number of tyres to be replaced?</h3>
In this problem we must use an inequality of the form f(x) ≥ a, where f(x) is the difference between the number of tyres replaced by Jim and the number of tyres replaced by Chris:
(25/20) · x - x ≥ 3
(5/20) · x ≥ 3
x ≥ 12
Then, the <em>minimum</em> number of tyres to be replaced is n = 15 + 12 = 17 tyres.
To learn more on inequalities: brainly.com/question/20383699
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Answer
given,
work = 5 J
spring stretch form 30 cm to 39 cm

x = 0.39 - 0.30 = 0.09 m


k = 1234.568 N/m
a) work when spring is stretched from 32 cm to 34 cm
x₂= 0.34 -0.30 = 0.04 m
x₁ = 0.32 - 0.30 = 0.02


W = 0.741 J
b) F = k x
25 = 1234.568 × x
x = 0.0205 m
x = 2.05 cm
90-n=3n
90=4n
22.5=n
Final answer 22.5