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Anna007 [38]
2 years ago
8

Goals scored by a hockey team in successive matches are 5,7,4,2,4,0,5,5 and 3. What is the number of goals, the team must score

in 10th match in order that the average comes to 4goals per match?
Mathematics
1 answer:
Stels [109]2 years ago
6 0

Answer:

5

Step-by-step explanation:

Total goals /total no. of matches = 4

5+7+4+2+4+0+5+5+3+x / 10 = 4

35 + x = 4 × 10

x = 40 - 35

x = 5

So, the team must score 5 inorder to get the average of 4 goals per match.

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600 by 375

Step-by-step explanation:


7 0
3 years ago
PLEASE HELP NOW<br> Solve the equation, then choose the correct answer: <br> -4(8 + 3y ) = 112
wolverine [178]

Answer:

y = -12

Step-by-step explanation:

-4 (8+3y) = 112

-32 -12y = 112

-12y = 144

y = -12

6 0
3 years ago
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How do I solve |5-3p|+9=13p+8
anastassius [24]

Answer:

p = -2/5 or 3/8

Step-by-step explanation:

|5 − 3p| + 9 = 13p + 8

|5 − 3p| = 13p − 1

If 5 − 3p is positive:

5 − 3p = 13p − 1

6 = 16p

p = 3/8

If 5 − 3p is negative:

-(5 − 3p) = 13p − 1

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-4 = 10p

p = -2/5

Alternatively, we can square both sides of the equation:

(5 − 3p)² = (13p − 1)²

25 − 30p + 9p² = 169p² − 26p + 1

0 = 160p² + 4p − 24

0 = 40p² + p − 6

0 = (5p + 2) (8p − 3)

p = -2/5 or 3/8

8 0
3 years ago
This is the numbers 3-4
Shtirlitz [24]

Answer:

3) x= 3, -2

4) 36

Step-by-step explanation:

3) x= 3, -2

4) 36

6 0
2 years ago
Factorise 15x + 35y - 40 z
xxTIMURxx [149]
Put number five as a common factor.

15x + 35y + 40z = 5 . 3x + 5 .7y + 5 .8z

= 5 . ( 3x + 7y + 8z )
4 0
3 years ago
Read 2 more answers
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