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3 years ago

4+ 2x = 12; ( 2) having trouble with dis :(

1 answer:

5 0

4 + 2x = 12

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Take away 4 from both sides:
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2x = 8

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Divide by 2 on both sides:
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x = 4

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Answer: x = 4
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V = the square root of 2as Solve for s

Gnom [1K]

As, v=√2as
Squaring both sides,
v²=2as
∴ s= v²/2a

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3 years ago

Express answer in exact form. Show all work for full credit.Find the area of one segment formed by a 6" square inscribed in a ci

Zinaida [17]

The area of the square is:

$\begin{gathered} As=6^2 \\ As=36in^2 \end{gathered}$

And the area of the circle is:

$\begin{gathered} Ac=\pi r^2 \\ Ac=\pi\cdot(3\sqrt[]{2})^2 \\ Ac=18\pi \end{gathered}$

The area of one segment is given by:

$\begin{gathered} A=\frac{Ac-As}{4} \\ A=\frac{18\pi-36}{4} \end{gathered}$

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2 years ago

g The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control

Rudiy27

Answer:

0.1426 = 14.26% probability that at least one of the births results in a defect.

Step-by-step explanation:

For each birth, there are only two possible outcomes. Either it results in a defect, or it does not. The probability that a birth results in a defect is independent of any other birth. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC).

This means that $p = \frac{1}{33}$

A local hospital randomly selects five births.

This means that $n = 5$

What is the probability that at least one of the births results in a defect?

This is:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(\frac{1}{33})^{0}.(\frac{32}{33})^{5} = 0.8574$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.8574 = 0.1426$

0.1426 = 14.26% probability that at least one of the births results in a defect.

4 0

3 years ago

!! How could it be s

Nataly_w [17]

The solution to the system of equations are (2, 5).

Solution:

The system of equations are

x + y = 7 – – – – (1)

2x – y = –1 – – – – (2)

To find x from equation (1):

x + y = 7

Subtract y from both sides of the equation, we get

⇒ x + y – y = 7 – y

⇒ x = 7 – y – – – (3)

Substitute (3) in (2) we get,

2(7 – y) – y = –1

14 – 2y – y = –1

14 – 3y = –1

Subtract 14 from both sides,

–3y = –15

Divide by –5 on both sides,

y = 5

Substitute y = 5 in equation (3)

x = 7 – 5

x = 2

The solution to the system of equations are (2, 5).

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3 years ago

Two math teachers come together and write math problems about fruit vendors. If Teacher A can write 50 problems in 60 minutes an

Fudgin [204]

Answer:

Step-by-step explanation:

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3 years ago

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