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3 years ago

4+ 2x = 12; ( 2) having trouble with dis :(

1 answer:

5 0

4 + 2x = 12

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Take away 4 from both sides:
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2x = 8

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Divide by 2 on both sides:
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x = 4

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Answer: x = 4
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Sid starts with savings of £13

MAVERICK [17]

Answer:

The savings of Sid and Tim will be in 17:9 in 6 weeks.

Step-by-step explanation:

Initial savings of Sid = £ 13

Initial savings of Tim = £ 0

For each successive week Sid saved = £ 3.5

For each successive week Tim saved = £ 3

Let us assume that after "x weeks" the amounts of Sid and Tim are in ratio 17:9.

If Sid saves £ 3.5 in one week, in x weeks he will £ 3.5x. Since he had £ 13 initially, total amount he would have in x weeks will be £ (13 + 3.5x)

If Time saves £ 3 one week, in x weeks he will save £ 3x. Since, he didn't have any money initially, in x weeks he would have saved £ 3x

The ratio of their savings in x weeks would be 17:9

So,

Sid's saving : Tim's saving = 17 : 9

Using the values of expressions, we get:

$13+3.5x:3x=17:9\\\\\frac{13+3.5x}{3x}=\frac{17}{9}\\\\ 9(13+3.5x)=17(3x)\\\\ 117+31.5x=51x\\\\ 117=51x-31.5x\\\\ 117=19.5x\\\\ x=\frac{117}{19.5}\\\\ x=6$

This means, the savings of Sid and Tim will be in 17:9 in 6 weeks.

5 0

3 years ago

Find the integral, using techniques from this or the previous chapter.<br> ∫x(8-x)3/2 dx

Soloha48 [4]

Answer:

$\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C$

Step-by-step explanation:

For this case we need to find the following integral:

$\int x(8-x)^{3/2}dx$

And for this case we can use the substitution $u = 8-x$ from here we see that $du = -dx$ , and if we solve for x we got $x = 8-u$ , so then we can rewrite the integral like this:

$\int x(8-x)^{3/2}dx= \int (8-u) u^{3/2} (-du)$

And if we distribute the exponents we have this:

$\int x(8-x)^{3/2}dx= - \int 8 u^{3/2} + \int u^{5/2} du$

Now we can do the integrals one by one:

$\int x(8-x)^{3/2}dx= -8 \frac{u^{5/2}}{\frac{5}{2}} + \frac{u^{7/2}}{\frac{7}{2}} +C$

And reordering the terms we have"

$\int x(8-x)^{3/2}dx= -\frac{16}{5} u^{\frac{5}{2}} +\frac{2}{7} u^{\frac{7}{2}} +C$

And rewriting in terms of x we got:

$\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C$

And that would be our final answer.

8 0

2 years ago

What is 2/4 as a decimal and percent

galben [10]

.5 as a decimal and 50% as a percent

3 0

3 years ago

Read 2 more answers

Each students in class 38 students was asked to report how many siblings he has. Data a 0/38 Data b 1/38 Data c 13/38 Data 8/38

Nezavi [6.7K]

Answer:

8/38

Step-by-step explanation:

You got it right, trust yourself

4 0

3 years ago

Samuel's car usually takes about 12.5 gallons of gas to fill it up when it's empty while driving through Canada Samuel notice th

nika2105 [10]

Answer: 47.4 liters

Step-by-step explanation:

From the question, we are informed that Samuel's car usually takes about 12.5 gallons of gas to fill it up when it's empty and while in Canada, he noticed that one liter is equivalent to 0.264 gallons.

The number of liters it'll take to fill Samuels car will be:

= 12.5/0.264

= 47.4 litres

7 0

3 years ago