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DedPeter [7]
3 years ago
9

Free brainlist for the first one

Mathematics
2 answers:
borishaifa [10]3 years ago
5 0

Answer:

YES

Step-by-step explanation:

Lunna [17]3 years ago
3 0

Answer:

i mean ill take it

Step-by-step explanation:

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tester [92]

Answer: h=P/mg

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7 0
3 years ago
What is 6 percent of 1,600,00 dollars
yarga [219]

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96

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7 0
3 years ago
Read 2 more answers
Use the given frequency table to find mean, median,mode,and range.
galina1969 [7]

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Mode:6

median: 5.5

mean: 5.25

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7 0
2 years ago
If line AD is a tangent to circle B at point C, and m ABC = 55°, what is the measure of BAD?
nikdorinn [45]

Answer:

145°

Step-by-step explanation:

There are a couple of ways you can get there:

1. ∠ACB is a right angle, 90°. Hence, ∠BAC is the complement of ∠ABC, so is ...

... ∠BAC = 90° -∠ABC = 90° -55° = 35°

Then, ∠BAC and ∠BAD are a linear pair, so total 180°. That makes ∠BAD the supplement of ∠BAC, so ...

... ∠BAD = 180° -35° = 145°

2. ∠BAD is the exterior angle at A for the triangle ABC. It will have a measure that is the sum of the opposite interior angles: given ∠ABC = 55° and right angle ACB = 90°.

... ∠BAD = 55° +90° = 145°

8 0
3 years ago
From a group of 13 women and ​12 men, a researcher wants to randomly select 8 women and 8 men for a study. In how many ways can
Fantom [35]

The total number of ways the study can be selected is: 637065

Given,

Total number of women in a group= 13

Total number of men in a group = 12

Number of women chosen = 8

Number of men chosen = 8

∴ the total number of ways the study group can be selected = 13C₈ and 12C₈.

This in the form of combination factor = nCr

                                                     ∴ nCr = n!/(n₋r)! r!

13C₈ = 13!/(13 ₋ 8)! 8!

        = 13!/5!.8!

        = 1287

12C₈ = 12!/(12₋8)! 8!

        = 12!/5! 8!

        = 495

Now multiply both the combinations of men and women

= 1287 × 495

= 637065

Hence the total number of ways the study group is selected is 637065

Learn more about "Permutations and Combinations" here-

brainly.com/question/11732255

#SPJ10

4 0
2 years ago
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