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3 years ago

NEED ANSWER ASAP, pls

Mathematics

1 answer:

BigorU [14]3 years ago

4 0

Answer:

Sammy needs to pay his mom 5 dollars each time he breaks a rule. His mom will make one exception and only take 2 dollars one time. y represents the total money paid and x is the number of times sammy broke a rule.

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Write an equation that defines the function :)

xenn [34]

Answer:

see below

Step-by-step explanation:

Since the initial value is 5 and it increases by 3 every time x goes up the equation is y = 5 * 3^x.

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3 years ago

For question 3, is it right though? Thankss

pishuonlain [190]

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3 years ago

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soldi70 [24.7K]

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3 years ago

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Which expression is equivalent to (x Superscript one-half Baseline y Superscript negative one-fourth Baseline z) Superscript neg

Darina [25.2K]

By using exponent properties, we will get the simplified expression:

$x^{-1}*y^{1/2}*z^2$

<h3>How to simplify the given expression?</h3>

Here we have the expression:

$(x^{1/2}*y^{-1/4}*z)^{-2}$

Remember the exponent properties:

$(a^n)^m = a^{n*m}$

And:

$(a*b)^n = (a^n)*(b^n)$

So using these two properties, we can rewrite:

$(x^{1/2})^{-2}*(y^{-1/4})^{-2}*(z)^{-2}\\\\(x^{-2*1/2})*(y^{-2*-1/4})*(z^{-2}})\\\\x^{-1}*y^{1/2}*z^2$

So we conclude that the completely simplified expression is:

$x^{-1}*y^{1/2}*z^2$

If you want to learn more about exponents:

brainly.com/question/8952483

#SPJ1

8 0

2 years ago

2. Consider the circle x^2−4x+y^2+10y+13=0. There are two lines tangent to this circle having a slope of 2/3.

likoan [24]

Answer:

a) The coordinates are (0.431, -2.646) and (3.568,-7.354)

b) The tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

Step-by-step explanation:

First, lets complete squares, by taking for each cordinate the square of a linear expression

0= x²−4x+y²+10y+13 = (x-2)²+ 4 + (y+5)²-25+13 = (x-2)²+(y+5)² - 8

Hence (x-2)² + (y+5)² = 8

Lets put y in function of x. We should obtain 2 functions f and g that represent the circle.

(y+5)² = 8 - (x-2)² = -x² + 4x + 4

$y = ^+_- \sqrt{-x^2+4x+4} -5$

Thus

$f(x) = \sqrt{-x^2+4x+4} - 5$

$g(x) = -\sqrt{-x^2+4x+4} - 5$

Lets find the derivate of each function and the points in which they reach the value 2/3. In those points the tangent line will have a slope of 2/3.

We may just find the values of x which the derivate of f is either 2/3 or -2/3.

$\frac{-x+2}{\sqrt{-x^2+4x+4}} = ^+_-\frac{2}{3} \Leftrightarrow \frac{x^2-4x+4}{-x^2+4x+4} = \frac{4}{9} \Leftrightarrow 9(x^2-4x+4) = 4(-x^2+4x+4) \\\Leftrightarrow 13x^2-52x+20 = 0$

The quadratic has roots

$\frac{52 ^+_-\sqrt{1664}}{26}$

one root is 3.568, which corresponds with g, and the other root is 0.431, corresponding to f.

Also g(3.568) = - 7.354 and f(0.431) = -2.646

This means that the coordinates are (0.431 , -2.646), (3.568 , -7.354) and the tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

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3 years ago