1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alexandra [31]
3 years ago
7

Given: AD = BC and AD || BC

Mathematics
1 answer:
bearhunter [10]3 years ago
4 0

Answer:

ABCD is a parallelogram.

Step-by-step explanation:

A parallelogram is a quadrilateral that has two parallel and equal pairs of opposite sides.    

From the given diagram,

Given: AD = BC and AD || BC, then:

i. AB = DC (both pairs of opposite sides of a parallelogram are congruent)

ii. <ADC = < BCD and < DAB = < CBA

thus, AD || BC and AB || DC (both pairs of opposite sides of a parallelogram are parallel)

iii. < BAC = < DCA (alternate angle property)

iv. Join BD, line AC  and BC are the diagonals of the quadrilateral which bisect each other. The two diagonals are at a right angle to each other.

v. <ADC + < BCD + < DAB + < CBA = 360^{0}  (sum of angles in a quadrilateral equals 4 right angles)

Therefore, ABCD is a parallelogram.

You might be interested in
How does graphing linear inequalities differ from graphing linear equations?​
Ivan

Explanation:

When the inequality symbol is replaced by an equal sign, the resulting linear equation is the boundary of the solution space of the inequality. Whether that boundary is included in the solution region or not depends on the inequality symbol.

The boundary line is included if the symbol includes the "or equal to" condition (≤ or ≥). An included boundary line is graphed as a solid line.

When the inequality symbol does not include the "or equal to" condition (< or >), the boundary line is not included in the solution space, and it is graphed as a dashed line.

Once the boundary line is graphed, the half-plane that makes up the solution space is shaded. The shaded half-plane will be to the right or above the boundary line if the inequality can be structured to be of one of these forms:

  • x > ...   or   x ≥ ...   ⇒ shading is to the right of the boundary
  • y > ...   or   y ≥ ...   ⇒ shading is above the boundary

Otherwise, the shaded solution space will be below or to the left of the boundary line.

_____

Just as a system of linear equations may have no solution, so that may be the case for inequalities. If the boundary lines are parallel and the solution spaces do not overlap, then there is no solution.

_____

The attached graph shows an example of graphed inequalities. The solutions for this system are in the doubly-shaded area to the left of the point where the lines intersect. We have purposely shown both kinds of inequalities (one "or equal to" and one not) with shading both above and below the boundary lines.

6 0
3 years ago
Suppose it takes 45 hours for robot A to construct a new robot. Working together with robot B, it takes 25 hours for both robots
Len [333]

Answer:

56 hours 25 minutes

Step-by-step explanation:

Given:

Suppose it takes 45 hours for robot A to construct a new robot

It takes 25 hours for both robots to construct a new robot.

Question asked:

How long would it take robot B to construct a new robot, working alone ?

Solution:

Let the time taken by robot B to construct new robot = x

<u>By robot A</u>

It takes 45 hours to construct = 1 new robot

It takes 1 hour to construct = \frac{1}{45} \ new\ robot

<u>By robot B</u>

It takes x hours to construct = 1 new robot

It takes 1 hour to construct = \frac{1}{x} new robot

<u>By working together</u>

It takes 25 hours to construct = 1 new robot

It takes 1 hour to construct = \frac{1}{25} \ new\ robot

\frac{1}{25} new robot is constructed in = 1 hour

<u><em>New robot is constructed by both working together in 1 hour = New robot is constructed by robot A in 1 hour + New robot is constructed by robot B in 1 hour </em></u>

\frac{1}{25} =\frac{1}{45} +\frac{1}{x} \\

Subtracting both sides by \frac{1}{45}

\frac{1}{25}-\frac{1}{45} =\frac{1}{45} -\frac{1}{45}+\frac{1}{x} \\\\\frac{1}{25}-\frac{1}{45} =\frac{1}{x}\\\\ Taking\ LCM \ of \ 25\ and\ 45,\ we\ got\ 225

\frac{9-5}{225} =\frac{1}{x} \\ \\ \frac{4}{225} =\frac{1}{x}\\\\ By\ cross \ multiplication\\4\times x=225\\Dividing\ both\ sides\ by\ 4\\x=56.25\ hours

Thus, robot B would take 56 hours 25 minutes to construct a new robot, working alone.

4 0
3 years ago
Read 2 more answers
PLEASE HELP!!!
baherus [9]

Answer:

is 26

Step-by-step explanation:

because i said

7 0
3 years ago
1,500 grams to kilograms
kakasveta [241]
1,500 grams is equal to 1.5 kilograms
8 0
4 years ago
Read 2 more answers
Wite a numerical expression for the below problems. Simplify the expressions.
ziro4ka [17]

Answer:

1) 9

2) 34

Step-by-step explanation:

For the first one, it would be

= (6×3)/2

= 18/2

= 9

The second one is,

= 36- (12/6)

= 36 - 2

= 34

4 0
3 years ago
Other questions:
  • What is the sum of the last four terms of the series 7+9+11+...+21
    5·1 answer
  • What is the equation 12xyz – 45? A. monomial. B. constant. C. trinomial. D. binomial.
    11·1 answer
  • A library has at least 900 square feet to create a new study area. Each study cubicle uses 6 square feet, and each computer stat
    10·1 answer
  • Find the equation of the line in slope intercept form parallel to 5x−5y=−2 and goes through the point (−10,4) y=?
    12·1 answer
  • A(-2,3)
    5·1 answer
  • Find the interest earned for $650 at 2% for 6 years
    11·2 answers
  • What is 2/3 dividend by 1/2?<br><img src="https://tex.z-dn.net/?f=%20%5Cdiv%20" id="TexFormula1" title=" \div " alt=" \div " ali
    8·1 answer
  • What is the value of the expression 1/2(12.g)-h when g=1/4 and h=1/2​
    14·1 answer
  • The revenue, in dollars, of a company that manufactures televisions can be modeled by the polynomial 3x²+180x . The cost, in dol
    5·1 answer
  • Select the situation that have a unit rate equivalent to 3 units to 1 unit
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!