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goldfiish [28.3K]
3 years ago
13

The value of a baseball player's rookie card began to increase once the player retired. When he retired in 1999 his card was wor

th $4.99. The value has increased by $1.73 each year since then. Express the relationship relating the value of the card y in dollars and the number of years x the player has been in retirement with an equation. Is the relationship between x and y proportional? What was the value of the card in 2006? Express the relationship with an equation. y=(Use integers or decimals for any numbers in the expression.)​
Mathematics
1 answer:
Leni [432]3 years ago
5 0

Answer: $15.37

Yes, proportional

Step-by-step explanation:

Ok So the Equation Here is

y = 1.73x + 4.99

The reason why 4.99 doesn't have a variable is because of the fact it's not being manipulated by time like the 1.73 is. It's a flat rate of 4.99 for the card itself, no increase or decrease in years. However, the 1.73 is affected by how ever many years the player is in retirement. That's why it has X because the amount of 1.73 needs to be multiplied by however many years hes been in retirement.

So Substitute 6 (because 2006 is what year we need to find) for x and we get

y = 1.73(6) + 4.99

Which if you simplify in a calculator or do it in your paper, comes out to be $15.37

*If this Helped I'd Also Appreciate 5* and a ♥ Thanks!*

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Check the picture below.

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\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[-3-(-6)]^2+[6-3]^2}\implies d=\sqrt{(-3+6)^2+(6-3)^2} \\\\\\ d=\sqrt{9+9}\implies \boxed{d=\sqrt{18}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-1})~\hfill d=\sqrt{[-2-(-6)]^2+[-1-3]^2} \\\\\\ d=\sqrt{(-2+6)^2+(-1-3)^2}\implies d=\sqrt{16+16}\implies \boxed{d=\sqrt{32}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{(\sqrt{18})(\sqrt{32})}\implies \sqrt{18\cdot 32}\implies \sqrt{576}\implies 24

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