Answer:
0.143
Step-by-step explanation:
You need to convert 1/7 to have a denominator of either 100 or 10. We can do 100.
1/7 = ?/100
then you need to divide 100/7 to find the scale factor which in this case is 14.286
then you can insert it into the equation
1/7 = 1 * 14.286/100
you end up with
14.286/100
then you can dived the two
0.14286 is what you end up with
but since it says rounded to the 3rd decimal place you go to the 3rd which is 2.
To round it you look at the 4th number which is 8.
<em>5 and above give it a shove up</em>
So now its 0.143
Hope this helped :)
Answers:Part A: The value of x is 0.Part B: X can be any real number.
In Part A, you have to first evaluate 7^2. This is 49. Now, write the equation 49^x = 1. We know that if you raise any number to 0, then the answer is 1.
In Part B, you have to first evaluate 7^0, that is 1. Now, we have the equation 1^x = 1. In this case, 1 raised to any exponent is still only 1. Imagine 1^17, this would be 1 times itself 17 times or just 1.
Therefore any number will work in Part B.
A function is differentiable if you can find the derivative at every point in its domain. In the case of f(x) = |x+2|, the function wouldn't be considered differentiable unless you specified a certain sub-interval such as (5,9) that doesn't include x = -2. Without clarifying the interval, the entire function overall is not differentiable even if there's only one point at issue here (because again we look at the entire domain). Though to be fair, you could easily say "the function f(x) = |x+2| is differentiable everywhere but x = -2" and would be correct. So it just depends on your wording really.
Answer:
The simplified form of the expression is ![\sqrt[3]{2x}-6\sqrt[3]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2x%7D-6%5Csqrt%5B3%5D%7Bx%7D)
Step-by-step explanation:
Given : Expression ![7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}](https://tex.z-dn.net/?f=7%5Csqrt%5B3%5D%7B2x%7D-3%5Csqrt%5B3%5D%7B16x%7D-3%5Csqrt%5B3%5D%7B8x%7D)
To Simplified : The expression
Solution :
Step 1 - Write the expression
Step 2- Simplify the roots and re-write as
and 
![7\sqrt[3]{2x}-3\times2\sqrt[3]{2x}-3\times2\sqrt[3]{x}](https://tex.z-dn.net/?f=7%5Csqrt%5B3%5D%7B2x%7D-3%5Ctimes2%5Csqrt%5B3%5D%7B2x%7D-3%5Ctimes2%5Csqrt%5B3%5D%7Bx%7D)
Step 3- Solve the multiplication
![7\sqrt[3]{2x}-6\sqrt[3]{2x}-6\sqrt[3]{x}](https://tex.z-dn.net/?f=7%5Csqrt%5B3%5D%7B2x%7D-6%5Csqrt%5B3%5D%7B2x%7D-6%5Csqrt%5B3%5D%7Bx%7D)
Step 4- Taking ![\sqrt[3]{2x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2x%7D)
common from first two terms
![\sqrt[3]{2x}(7-6)-6\sqrt[3]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2x%7D%287-6%29-6%5Csqrt%5B3%5D%7Bx%7D)
Therefore, The simplified form of the expression is
