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3 years ago

14

jerome bought 2 postcards and received $1.35 in change in quarters and dimes. If he got coins back, how many of each coin did he

get?

1 answer:

Butoxors [25]3 years ago

7 0

There are many possibilities

11 dimes and 1 quarter

6 dimes and 3 quarters

1 dime and 6 quarters

Much more...

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Solve for x please. I need step-by-step explanation. Thank you.

Amiraneli [1.4K]

Step-by-step explanation:

$(7x)^x=7^{7^7}$

<u>log both sides:</u>

$log_7(7x)^x=log_7(7^{7^7})$
$xlog_7(7x)=7^7$
$x(1 +log_7x) = 7*7^6$
$x(1 +log_7x) = 7^6(1+6)$
$x(1 +log_7x) = 7^6(1+log_77^6)$

<u>Compare both sides to get:</u>

$x=7^6$

or

$x=117649$

4 0

2 years ago

I will give you a brainlyist if you salve and 50 points and 5 stars plz help

Diano4ka-milaya [45]

Answer:

1. X= 56

2. X= -11/2 (When you solve you get this if you need it as a mixed number it's X= -5 1/2

Step-by-step explanation:

simplifying means: Reducing to lowest terms.

To solve for x simplify both sides of the equation, then isolate the variable.

4 0

2 years ago

George has $49 which he decides to spend on x and y. commodity x costs $5 per unit and commodity y costs $11 per unit. he has th

FromTheMoon [43]

We are given the equations:

<span>5 x + 11 y = 49 --> eqtn 1</span>

<span>u = 3 x^2 + 6 y^2 --> eqtn 2</span>

Rewrite eqtn 1 explicit to y:

11 y = 49 – 5 x

<span>y = (49 – 5x) / 11 --> eqtn 3</span>

Substitute eqtn 3 to eqtn 2:

u = 3 x^2 + 6 [(49 – 5x) / 11]^2

u = 3 x^2 + 6 [(2401 – 490 x + 25 x^2) / 121]

u = 3 x^2 + 14406/121 – 2940x/121 + 150x^2/121

u = 4.24 x^2 – 24.3 x + 119.06

Derive then set du/dx = 0 to get the maxima:

du/dx = 8.48 x – 24.3 = 0

solving for x:

8.48 x = 24.3

x = 2.87

so y is:

y = (49 – 5x) / 11 = (49 – 5*2.87) / 11

y = 3.15

Answer:

<span>George will choose some of each commodity but more y than x.</span>

7 0

3 years ago

A typical sugar cube has an edge length of 1.00 cm. Imagine you have a cubical box that contains a mole of sugar cubes, perfectl

alisha [4.7K]

Answer:

844368.7 m

Step-by-step explanation:

We are given that a typical sugar cube has an edge length of 1.00 cm.

We have to find the edge length of the box in meters.

Edge length of sugar cube=1 cm = $10^{-2}m$ ( $1 cm=\frac{1}{100}m$ )

Volume of a sugar cube= $side\times side\time side=(10^{-2})^3=10^{-6}m^3$

1 mole of sugar= $6.02\times 10^{23}units$

Volume of 1 unit= $10^{-6} m^3$

Volume of $6.02\times 10^{23}$ units= $6.02\times10^{23}\times 10^{-6}=6.02\times 10^{17} m^3$

Volume of box=1 mole of sugar= $6.02\times 10^{17} m^3$

Edge length of box= $\sqrt[3]{6.02\times 10^{17}}=844368.7 m$

6 0

3 years ago

The number of hours per week that the television is turned on is determined for each family in a sample. The mean of the data is

Zigmanuir [339]

I don’t know skip that question

7 0

2 years ago