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Tresset [83]
3 years ago
13

The given line segment has a midpoint at (−1, −2).

Mathematics
2 answers:
Hunter-Best [27]3 years ago
8 0

Answer:

y = -4(x) - 6

Step-by-step explanation:

For anyone looking for a simple answer.

N76 [4]3 years ago
4 0

Answer:

The equation of the perpendicular line is y = −4(x) − 6

Step-by-step explanation:

Given:

Three coordinates points (in pair).

Lets choose two points,in (x,y) format.

Where

(x,y) = (-5,-3) and (x_1,y_1) = (3,-1)

From these points we will find the slope using point-slope formula.

That is :

(y_1-y)=m(x_1-x)

m=\frac{(y_1-y)}{(x_1-x)}

Plugging the values:

m=\frac{-1+3}{3+5}=\frac{1}{4}

Now we know that product of slope of two perpendicular lines = -1.

So the slope of the line which is perpendicular (m_1) .

m_1=\frac{-1}{m}

m_1=\frac{-1}{\frac{1}{4} } =-1\times \frac{4}{1} =-4

Now using this slope we will plug the midpoint (-1,-2) values in point-slope form and reduced it to slope intercept.

y-(-2)=-4(x+1)

y+2=-4x-4

y=-4x-4-2

y=-4x-6

So the equation of the perpendicular bisector is y = -4(x) - 6

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zavuch27 [327]

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3 years ago
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victus00 [196]

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360

Step-by-step explanation:

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When the distributive property is applied, which number completes the statement correctly?
maxonik [38]
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3 years ago
ABCD is a trapezium with AB parallel to CD. Find the value of x and the value of y.
Natasha2012 [34]

Answer:

x = 107 , y = 60

Step-by-step explanation:

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3 0
3 years ago
. Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals intersect at point P. Side QR = 17m, diagonal QS
trapecia [35]

Answer:

495 meter²

Step-by-step explanation:

In the given kite QRST,

PQ = PS = 15 meter

QR = 17 meter

We have to find the area of the kite.

Since kite is in the form of a rhombus.

and rhombus is = \frac{1}{2}  (Diagonal QS) × (Diagonal RT)

In Δ QRP,

17² = 15² + RP²

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RP=\sqrt{289-225}

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So RT = RP + PT = 8 + 25 = 33 meter.

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6 0
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