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3 years ago

PLEASE HELP FOR BASKETBALL EINSTEINE

Mathematics

2 answers:

Karo-lina-s [1.5K]3 years ago

8 0

The constant term in the given equation is -3. This is the point where the graph must cross the y-axis. Graph B crosses at +3, so is not the answer.

The coefficient of x is 3/4. This means the line rises 3 units in 4 horizontal units. The line in Graph C appears to rise 3 units in 2 horizontal units, so is not the answer.

Graph A has the correct y-intercept and slope, so is the correct choice.

Furkat [3]3 years ago

7 0

Answer:

$Graph \: A$

Step-by-step explanation:

I am here for you!!!

Starting from the y-intercept of [0, −3], the graph did rise\run by moving either moving three blocks south over four blocks west, or three blocks north over four blocks east [west and south are negatives].

I am joyous to assist you anytime.

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A regular hexagonal prism has an edge length 12 cm, and height 10 cm. Identify the volume of the prism to the nearest tenth.

Alexeev081 [22]

Check the picture below.

so the volume will simply be the area of the hexagonal face times the height.

$\textit{area of a regular polygon}\\\\ A=\cfrac{1}{4}ns^2\stackrel{\qquad degrees}{\cot\left( \frac{180}{n} \right)}~~ \begin{cases} n=\stackrel{number~of}{sides}\\ s=\stackrel{length~of}{side}\\[-0.5em] \hrulefill\\ n=6\\ s=12 \end{cases}\implies A=\cfrac{1}{4}(6)(12)^2\cot\left( \frac{180}{6} \right) \\\\\\ A=216\cot(30^o)\implies A=216\sqrt{3} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the hexagon}}{(216\sqrt{3})}~~\stackrel{height}{(10)}\implies 2160\sqrt{3}~~\approx ~~3741.2~cm^3$

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2 years ago

Please help!! Will mark first answerer brainiest!! Thank you so much!!

geniusboy [140]

C. Is the answer to this question

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