Answer:
The mean will be increased by 5
Step-by-step explanation:
Suppose a set of data ![(2, 4, 6, 8, 10, 12)](https://tex.z-dn.net/?f=%282%2C%204%2C%206%2C%208%2C%2010%2C%2012%29)
Mean is defined as sum of all the values given set of data divided by total number of values.
Mean1 = ![\frac{2+4+6+8+10+12}{6} = \frac{42}{6} = 7](https://tex.z-dn.net/?f=%5Cfrac%7B2%2B4%2B6%2B8%2B10%2B12%7D%7B6%7D%20%3D%20%5Cfrac%7B42%7D%7B6%7D%20%3D%207)
Now if we add 5 toeach value, the new set becomes ![(7, 9, 11, 13, 15, 17)](https://tex.z-dn.net/?f=%287%2C%209%2C%2011%2C%2013%2C%2015%2C%2017%29)
for which,
Mean2 = ![\frac{7+9+11+13+15+17}{6} = \frac{72}{6} = 12](https://tex.z-dn.net/?f=%5Cfrac%7B7%2B9%2B11%2B13%2B15%2B17%7D%7B6%7D%20%3D%20%5Cfrac%7B72%7D%7B6%7D%20%3D%2012)
Mean2 - Mean1 = 5
Answer:
13818
I think that is your answer
Answer:
The length of the rhombus is =![\frac{bc}{b+c}cm](https://tex.z-dn.net/?f=%5Cfrac%7Bbc%7D%7Bb%2Bc%7Dcm)
Step-by-step explanation:
It is given that the Rhombus ADEF is inscribed into a triangle ABC so that they share angle A and the vertex E lies on the side BC.Then,
AE is the angle bisector of ∠A, so divides the sides of the triangle into a proportion:
![\frac{BE}{CE}=\frac{BA}{AC}=\frac{c}{b}](https://tex.z-dn.net/?f=%5Cfrac%7BBE%7D%7BCE%7D%3D%5Cfrac%7BBA%7D%7BAC%7D%3D%5Cfrac%7Bc%7D%7Bb%7D)
⇒![\frac{BE}{CE}=\frac{c}{b}](https://tex.z-dn.net/?f=%5Cfrac%7BBE%7D%7BCE%7D%3D%5Cfrac%7Bc%7D%7Bb%7D)
⇒![\frac{BE}{BC}=\frac{c}{c+b}](https://tex.z-dn.net/?f=%5Cfrac%7BBE%7D%7BBC%7D%3D%5Cfrac%7Bc%7D%7Bc%2Bb%7D)
Now, ΔDBE is similar to ΔABC, then
DE=![(\frac{BE}{BC}){\times}AC](https://tex.z-dn.net/?f=%28%5Cfrac%7BBE%7D%7BBC%7D%29%7B%5Ctimes%7DAC)
=![(\frac{c}{c+b}){\times}b](https://tex.z-dn.net/?f=%28%5Cfrac%7Bc%7D%7Bc%2Bb%7D%29%7B%5Ctimes%7Db)
=![\frac{bc}{b+c}cm](https://tex.z-dn.net/?f=%5Cfrac%7Bbc%7D%7Bb%2Bc%7Dcm)
Thus, the length of the rhombus is =![\frac{bc}{b+c}cm](https://tex.z-dn.net/?f=%5Cfrac%7Bbc%7D%7Bb%2Bc%7Dcm)