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nikitadnepr [17]
3 years ago
12

A student examines the triangle shown above. He notices that lines BE andCD look parallel. The student claims that they are para

llel by look aLone ?
Mathematics
1 answer:
irakobra [83]3 years ago
4 0
I can’t see any photo
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According to an​ airline, flights on a certain route are on time 80 ​% of the time. suppose 10 flights are randomly selected and
natulia [17]
<span>(a) This is a binomial experiment since there are only two possible results for each data point: a flight is either on time (p = 80% = 0.8) or late (q = 1 - p = 1 - 0.8 = 0.2).
​(b) Using the formula:</span><span>
P(r out of n) = (nCr)(p^r)(q^(n-r)), where n = 10 flights, r = the number of flights that arrive on time:
P(7/10) = (10C7)(0.8)^7 (0.2)^(10 - 7) = 0.2013
Therefore, there is a 0.2013 chance that exactly 7 of 10 flights will arrive on time.
​(c) Fewer than 7 flights are on time means that we must add up the probabilities for P(0/10) up to P(6/10).
Following the same formula (this can be done using a summation on a calculator, or using Excel, to make things faster):
P(0/10) + P(1/10) + ... + P(6/10) = 0.1209
This means that there is a 0.1209 chance that less than 7 flights will be on time.
​(d) The probability that at least 7 flights are on time is the exact opposite of part (c), where less than 7 flights are on time. So instead of calculating each formula from scratch, we can simply subtract the answer in part (c) from 1.
1 - 0.1209 = 0.8791.
So there is a 0.8791 chance that at least 7 flights arrive on time.
(e) For this, we must add up P(5/10) + P(6/10) + P(7/10), which gives us
0.0264 + 0.0881 + 0.2013 = 0.3158, so the probability that between 5 to 7 flights arrive on time is 0.3158.
</span>
6 0
3 years ago
Situation:A researcher in North America discoversa fossile that contains 65% of its originalamount of C-14..-ktN=NoeNo inital am
zheka24 [161]

SOLUTION

We have been given the equation of the decay as

\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}

So we are looking for the time

Plugging the values into the equation, we have

\begin{gathered} N=N_0e^{-kt} \\ 0.65N_0=N_0e^{-0.0001t} \\ e^{-0.0001t}=\frac{0.65N_0}{N_0} \\ e^{-0.0001t}=0.65 \end{gathered}

Taking Ln of both sides, we have

\begin{gathered} ln(e^{-0.000t})=ln(0.65) \\ -0.0001t=ln(0.65) \\ t=\frac{ln(0.65)}{-0.0001} \\ t=4307.82916 \end{gathered}

Hence the answer is 4308 to the nearest year

8 0
1 year ago
I know the answer but I don’t know how to set it up
vladimir2022 [97]

Answer: 4 x 16 = 64

16 + 44 = 60

I think..

Step-by-step explanation:

7 0
4 years ago
I need help with with problem please thanks!
liraira [26]
40 is the correct answer. Hope this helps :)
5 0
4 years ago
10×+73=7 solve two step equations by using inverse operations. and use inverse operations to solve the equations ​
MrMuchimi

Answer:

x=-67/10

Step-by-step explanation:

What you have to do is first subtract 73 from both sides. that makes it 10x=7-73. That is 10x=-67. Then divide both sides by 10. That is x=-67/10

Can I get brainliest

7 0
3 years ago
Read 2 more answers
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