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3 years ago

2/3 of my cats plus three

Mathematics

1 answer:

gladu [14]3 years ago

3 0

My answer -

3 2/3
Wow you have allot of cats LOL!!!

P.S
Have an AWESOME LGBT DAY !!! :)

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Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was

andrezito [222]

Answer:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 100, p = 0.42$

92% confidence level

So $\alpha = 0.08$ , z is the value of Z that has a pvalue of $1 - \frac{0.08}{2} = 0.96$ , so $Z = 1.75$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.3336$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.5064$

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

4 0

3 years ago

Please help me with this question

san4es73 [151]

Step-by-step explanation:

Given: $f'(x) = x^2e^{2x^3}$ and $f(0) = 0$

We can solve for f(x) by writing

$\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx$

Let $u = 2x^3$

$\:\:\:\:du=6x^2dx$

Then

$\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du$

$\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k$

We know that f(0) = 0 so we can find the value for k:

$f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}$

Therefore,

$\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)$

5 0

3 years ago

3. Tarzan went to the plant nursery and bought a tree that was initially 90 feet tall for his monkey friends to climb on.

frutty [35]

Answer:

ok im convuzed how do you buy a 90ft tree cuz that sounds fun

Step-by-step explanation:

pls lemme know

3 0

3 years ago

The owner of a chain of 12 restaurants wants to conduct a survey to determine whether his employees are properly informed by the

goldenfox [79]

Answer: non random and biased. Random and un biased

Step-by-step explanation:

Just answered it

8 0

3 years ago

Starting at 100% I have 82 clients 2 of them didn't get a check up what percent does that leave us at ?

murzikaleks [220]

82 total clients

2 did NOT get a checkup

(82 - 2) = 80 clients DID get a checkup

80/82 = 0.97561 = <em>97.561%</em> of your clients have had their checkup.

Interestingly, that's the exact same percentage of your clients who have had lunch. Perhaps ... I'm not stating this as a fact, but it's a hunch ... just maybe the other two have not had their checkups yet because they are out getting lunch.

4 0

3 years ago