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3 years ago

Can anyone help me with 9th-grade geometry?

Mathematics

1 answer:

katovenus [111]3 years ago

7 0

Answer:

See below.

Step-by-step explanation:

From the given info the 2 triangles are isosceles with AE = FR and ET = RP because the 2 sets of base angles are equal.

As the base angles are congruent m < E = m < R.

So the are 2 triangles are congruent by SAS, ASA and AAS.

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Solve the radical equation. which is an extraneous solution to the radical equation? x = −1 x = 1 x = 5 there are no extraneous

qwelly [4]

Hence, the correct option is (D)There are no extraneous solutions to the equation.

<h2>What is an expression?</h2>

expression is a combination of numbers, variables, and functions (such as addition, subtraction, multiplication or division etc.). This math operation can be addition, subtraction, multiplication, or division. The structure of an expression is: Expression is (Number/Variable, Math Operator, Number/Variable)

<h3>How to solve?</h3>

the correct option is (D)There are no extraneous solutions to the equation.

to learn more about expressions: brainly.com/question/1859113

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8 0

2 years ago

Please answer this question please

Bas_tet [7]

<h3>Answer:</h3><h3 /><h3>Amount = Rs 13891.50</h3><h3>Compound interest = Rs 1891.50</h3>

Step-by-step explanation:

C = Amount (A) - Principal (P)

Where

C is the compound interest

To find the amount we use the formula

$A = P ({1 + \frac{r}{100} })^{n}$

where

P is the principal

r is the rate

n is the period / time

From the question

P = Rs 12, 000

r = 5%

n = 3 years

Substitute the values into the above formula

That's

$A = 12000 ({1 + \frac{5}{100} })^{3} \\ A = 12000(1 + 0.05)^{3} \\ A = 12000 ({1.05})^{3}$

We have the answer as

<h3>Amount = Rs 13891.50</h3>

Compound interest = 13891.50 - 12000

<h3>Compound interest = Rs 1891.50</h3>

Hope this helps you

8 0

3 years ago

A bag contains 7 pieces of paper numbered 1 to 7. P(2)=. Is

pochemuha

Answer:

$P (2) =\frac{1}{7}$ Theoretical probability

Step-by-step explanation:

The theoretical probability is defined as:

$P = \frac{number\ of\ desired\ results}{number\ of\ possible\ results}$

In this case we look for the probability of taking a 2 out of the bag. As there is only one paper with the number 2 in the bag then:

number of desired results = 1

The amount of paper in the bag is equal to 7, so:

number of possible results = 7

Thus:

$P (2) =\frac{1}{7}$

This is a theoretical probability, since we do not need to perform the experiment to calculate the probability.

To calculate the experimental probability we must perform the following experiment:

Take a paper out of the bag, record the number obtained and then return the paper to the bag.

Now repeat this experiment n times. (Perform n trials)

So:

$P (2) = \frac{number\ of\ times\ you\ obtained\ the\ number\ 2}{number\ of\ trials\ performed}$

To calculate a theoretical probability you always need to perform an experiment with n trials.

5 0

3 years ago

The school is ordering 2,000 cupcakes to celebrate reading.the school can Oder the cupcakes in the sets of 10.how many sets of 1

aleksklad [387]

Answer:

200 sets of 10 can be ordered to complete the order of 2,000 cakes.

Step-by-step explanation:

Total numbers of cupcakes to be ordered = 2,000

The number of cupcakes in 1 set = 10

So, $\textrm{Total sets to be ordered} = \frac{\textrm{Total Cupcakes to be ordered}}{\textrm{Cupcakes in 1 set}}$

= $\frac{2,000}{10} = 200$

or, Number of cupcake sets = 200

Hence, 200 sets of 10 can be ordered.

3 0

4 years ago

If there are x teams in a sports league, and all the teams play each other twice, a total of n(x) games are played, where n

EleoNora [17]

1.
Consider a group of n objects. Assume we want to form groups of r, from these n objects.

There are in total $C(n, r)= \frac{n!}{r!(n-r)!}$ many ways of doing so.

where, r! is "r factorial", calculated as 1*2*3*...*(r-1)*r

2.

C(x, 2) is the total number of pairs out of x objects, that we can form.

so let the x objects represent the x teams, and 2, represent a group of 2, which means a game.

The total number of games is:

n(x)=2*C(x, 2) = $2* \frac{x!}{2!(x-2)!}= \frac{x!}{(x-2)!}= \frac{x(x-1)(x-2)!}{(x-2)!}=x(x-1)= x^{2} -x$

Remark, we multiplied by 2, since there will be 2 matches for each pair of teams.

Answer: $x^{2} -x$

6 0

3 years ago