For example, on Google you may see that "1.5 cubic foot boxes are the standard box, manufactured by most companies". So, we assume that a standard cardboard box is 1.5 feet tall.

So, if we set the equation

$1.5k = 5 \iff k=\dfrac{5}{1.5}=3.\bar{3}$

So, there would be between 3 and 4 cardboard boxes in a 5 feet tall stack.

Similarly, we can see that the average book is 9 inches tall. 9 inches are 0.75

feet, so we have

$0.75k=5 \iff k=6.\bar{6}$

So, there would be between 6 and 7 books in a 5 feet tall stack.

The average brick is 75 millimeters tall, which means 0.25 feet tall. Again, we have

$0.25k=5 \iff k=20$

So, there would be 20 bricks in a 5 feet tall stack.

Finally, a coin is about 0.006 feet, which leads to

$0.006k=5 \iff k=833.\bar{3}$

So, there would be between 833 and 834 coins in a 5 feet tall stack.

5 0

3 years ago

What can you say about the graph of the function below? check ALL that apply.

erastova [34]

I think that C and D are the correct answers

4 0

3 years ago

The data set represents the total number of people who bought bananas each hour at a grocery store.

balandron [24]

It's A. i just took the quiz.

6 0

3 years ago

Read 2 more answers

suppose 60% of kids who visit a doctor have a fever, and 20% of kids with a fever have sore throats. what's the probability that

kkurt [141]

Answer:

0.12

Step-by-step explanation:

Suppose there are 100 kids

60% have fever, so what is 60% of 100?

We convert percentage to decimal and multiply:

60/100 = 0.6

0.6 * 100 = 60 have fever

20% of the people having fever (60 of them) have sore throats, so,

What is 20% of 60?

We convert percentage to decimal and multiply:

20/100 = 0.2

0.2 * 60 = 12 have sore throat

So, how many people are there with fever AND sore throat, that is 12. We took initially there to be 100 people. Hence, the probability is:

$\frac{12}{100}=0.12$

3 0

3 years ago