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dimaraw [331]
3 years ago
8

Which values of P and Q result in an equation with exactly one solution?

Mathematics
2 answers:
amm18123 years ago
8 0
Another question for my impossible math question file.

All of the given pairs of values result in an equation with exactly one solution, as will any pair such that Q≠13 and P≠12.

For Q=13 and P≠12, there is no solution.
For Q=13 and P=12, there will be an infinite number of solutions.

lyudmila [28]3 years ago
3 0

Its all of the answers in that question


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Find the volume of the pyramid.
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Answer:

the answer is 280

Step-by-step explanation:

v=1w h/3

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Tyler gathered data from 12 recent basketball games about the number of points he scored, the number of points his teammate Nola
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Only plot B

Step-by-step explanation:

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3 years ago
F(x)=2^x. What is g(x)?
Alexxx [7]

The function g(x) is g(x)= (3x)^2

<h3>How to solve for g(x)?</h3>

The complete question is in the image


From the graph in the image, we have:

f(x) = x^2

The function f(x) is stretched by a factor of 3 to form g(x).

This means that:

g(x) = f(3x)

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g(x)= (3x)^2

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Read more about function transformation at:

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7 0
2 years ago
Find the set of solutions for the linear system.
Illusion [34]

Answer:

The system has infinitely many solutions.

\left\begin{array}{ccc}x_1&=&-\frac{1}{3}x_2-\frac{16}{9}x_4-\frac{2}{9}  \\x_2&=&s_1\\x_3&=&-\frac{4}{3}x_4+\frac{1}{3}  \\x_4&=&s_2\end{array}\right

Step-by-step explanation:

To find the solution for this system of linear equations -3x_1-x_2+4x_3=2\\-3x_3 - 4x_4 = -1you must:

Step 1: Transform the augmented matrix to the reduced row echelon form.

A matrix is a rectangular arrangement of numbers into rows and columns.

A system of equations can be represented by an augmented matrix.

In an augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

This is matrix that represents the system

\left[ \begin{array}{ccccc} -3 & -1 & 4 & 0 & 2 \\\\ 0 & 0 & -3 & 4 & -1 \end{array} \right]

The augmented matrix can be transformed by a sequence of elementary row operations to the matrix.

There are three kinds of elementary matrix operations.

  1. Interchange two rows (or columns).
  2. Multiply each element in a row (or column) by a non-zero number.
  3. Multiply a row (or column) by a non-zero number and add the result to another row (or column).

Using elementary matrix operations, we get that

Row Operation 1: Multiply the 1st row by -1/3

Row Operation 2: Multiply the 2nd row by -1/3

Row Operation 3: Add 4/3 times the 2nd row to the 1st row

\left[ \begin{array}{ccccc} 1 & \frac{1}{3} & 0 & \frac{16}{9} & - \frac{2}{9} \\\\ 0 & 0 & 1 & \frac{4}{3} & \frac{1}{3} \end{array} \right]

Step 2: Interpret the reduced row echelon form

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{ccccc} 1 & \frac{1}{3} & 0 & \frac{16}{9} & - \frac{2}{9} \\\\ 0 & 0 & 1 & \frac{4}{3} & \frac{1}{3} \end{array} \right]

which corresponds to the system

x_1+\frac{1}{3}x_2+ \frac{16}{9}x_4=-\frac{2}{9} \\x_3+ \frac{4}{3}x_4=\frac{1}{3}

We see that the variables x_2, x_4 can take arbitrary numbers; they are called free variables. Let x_2=s_1, x_4=s_2. All solutions of the system are given by

\left\begin{array}{ccc}x_1&=&-\frac{1}{3}x_2-\frac{16}{9}x_4-\frac{2}{9}  \\x_2&=&s_1\\x_3&=&-\frac{4}{3}x_4+\frac{1}{3}  \\x_4&=&s_2\end{array}\right

The system has infinitely many solutions.

8 0
4 years ago
Samantha had a board that was 6 ft 8 in long . she cut off a piece that was 2 ft 10 in.long . how much board does she have
agasfer [191]
B, 4ft 10 in
Hope this helped
7 0
4 years ago
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