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torisob [31]
4 years ago
9

The second angle of a triangular field is three times as large as the first angle. the third angle is 40⁰ greater than the first

angle. How long are the angles?
Mathematics
1 answer:
vagabundo [1.1K]4 years ago
8 0
Every triangle always consists of three angles which altogether give 180⁰. Let's say that:

Angle 1 = x
Angle 2 = 3x
Angle 3 = x + 40

180 = x + 3x + x + 40
180 = 5x + 40       / - 40 (both sides)
140 = 5x              / : 5 (both sides)
x = 28

Angle 1 = 28
Angle 2 = 3 * 28 = 84
Angle 3 = 28 + 40 = 68

Let's check if it gives us 180⁰:

28 + 84 + 68 = 180

So it's correct :)
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a man pushes his car with a force of 30N to the right. He moves the car a distance of 3 meter to the right. What is the amount o
Reika [66]

Given parameters:

Force  = 30N

Distance covered  = 3m

Unknown:

Work done = ?

Work done is an important physical quantity. It is formulated as the product of force and distance.

   Work done  = Force x Distance

The unit is in Joules.

Now go ahead and input the parameters;

                  Work done  = 30 x 3  = 90J

The work done in pushing the car is 90J

3 0
3 years ago
Calculator
Ann [662]

Answer:

10

Step-by-step explanation:

Vertical angles are equal to each other

-2x + 90 = x - 30

90 + 30 = x + 2x add like terms

120 = 3x divide both sides by 3

40 = x

angle <ZD is x - 30 so the answer is 10

6 0
3 years ago
Find the domain of the following functions and simplify their expressions.
erica [24]

The domain of the function is  (-∞,∞) and the simplified expression is x²-6x-40 .

A function's domain and range are its constituent parts. A function's  range is its potential output, whereas its domain is the set of all possible input values. Range, Domain, and Function. A is the domain and B is the co-domain if a function f: A B exists that maps every element of A to an element in B. 'b', where (a,b) R, provides the representation of an element 'a' under a relation R. The set of images is the function's range.

The given functions are

f(x)=6x+24

g(x)=x²-16

Now we have to find (g-f)(x) .

(g-f)(x)=x²-16-6x-24

or,(g-f)(x)=x²-6x-40

or,(g-f)(x)=x²-10x+4x-40

or,(g-f)(x)=x(x-10)+4(x-10)

or,(g-f)(x)=(x-10)(x+4)

So the domain of the function (g-f)(x) are the values for which the function exists. we can see that the function exists for all values of x.

Domain in set builder notation={x|x∈R}

Domain in interval notation=(-∞,∞)

To learn more about domain and range:

brainly.com/question/28135761

#SPJ9

7 0
1 year ago
Which of the following steps can be performed so that the square root property may easily be applied to 2x2 = 16? (1 point)
Ivan

Answer:

\Large \boxed{\mathrm{Option \ 2}}

Step-by-step explanation:

2x^2 =16

The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is x, so divide both sides by 2 before applying the square root property.

The x variable should be isolated on one side of the equation. The x variable is squared so before performing the square root property where we take the square root of both sides, we divide both sides by 2, then take the square root of both sides.

Dividing both sides by 2.

\displaystyle \frac{2x^2 }{2} =\frac{16}{2}

x^2 =8

Taking the square root of both sides.

\sqrt{x^2 } =\pm \sqrt{8}

x=\pm 2\sqrt{2}

7 0
3 years ago
Read 2 more answers
The Great Eagles of the Misty Mountains wish to estimate the mean number of orcs per raiding party. To do so, they measure the n
Anestetic [448]

Answer:

The Upper Bound of the 99% confidence interval about the mean number of orcs per raiding party is of 106.83 orcs per party.

Step-by-step explanation:

We have the standard deviation of the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 13 - 1 = 12

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 12 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 3.0545

The margin of error is:

M = T*s = 3.0545*7.8 = 23.83

In which s is the standard deviation of the sample.

The upper end of the interval is the sample mean added to M. So it is 83 + 23.83 = 106.83 orcs per party.

The Upper Bound of the 99% confidence interval about the mean number of orcs per raiding party is of 106.83 orcs per party.

7 0
4 years ago
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