One number<span> is eight </span>less than<span> five </span>times<span> another. </span>If the sum<span> of the </span>two numbers<span> is 28, find the </span><span>numbers . Please levae this i need points i have 0000
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Step-by-step explanation:
When x = -1
Substitute x = -1 into y = 2x
y = 2(-1)
y = -2
( -1, -2)
When x = 3
Substitute x = 3 into y = 2x
y = 2(3)
y = 6
( 3, 6)
There are six sides on each die. For each possible score on Die 1, there are six possible scores on Die 2. So the number of possible combinations is 6*6 = 36.
<span>It follows that if the dice are thrown 36 times, you would expect each combination to come up once. </span>
<span>We therefore simply need to know how many combinations add up to less than 5. (I've interpreted this as not including a total of 5 itself). </span>
<span>These combinations are: 1 and 1, 2 and 1, 1 and 2, 2 and 2, 3 and 1, and 1 and 3 ---> six combinations out of 36. </span>
<span>So you'd expect a sum less than 5 six times. </span>
Answer:
See below
Step-by-step explanation:
She could have each student in the class write his or her name on a slip of paper and put it in a bowl. Then, she could shake the bowl and pull out any slip of paper with a student's name on it. After 3 times, the random sample would be over, and Mrs. Purdue would have her 3 representatives.
let apple juice = x
milk = 2x
fruit punch = 3x
3x + 2x + x = 660
6x = 660
x = 660/6
x = 110 apple juices
2*110 = 220 milks
3*110 = 330 fruit punches
