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My name is Ann [436]
3 years ago
15

When sample size increases:____.

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
3 0

Answer:

D. Confidence interval decreases.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

When sample size increases:

The standard deviation of the sample mean is:

s = \frac{\sigma}{\sqrt{n}}

That is, it is inversely proportional to the sample size, so if the sample size incerases, the standard deviation decreases, and so does the confidence interval.

This means that the correct answer is given by option D.

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hello,

i advice you check the question again if it is GF(2^{4}) or GF(24). i believe the question should rather be in this form;

multiplication in GF(2^{4}): Compute A(x)B(x) mod P(x) = x^{4} + x+1, where A(x)=x^{2}+1, and B(x)=x^{3} + x+1.

i will solve the above question and i believe with this you will be able to solve any related problem.

A(x)B(x)=(x^{2} +1) (x^{3}+x+1) mod (x^{4}+x+1  ) = (x^{5} +x^{3}+x^{2}  ) + (x^{3}+x+1  ) mod (x^{4} + x+1 )

= x^{5}+2x^{3} +x^{2}  + x + 1 mod(x^{4}+x+1  )

=2x^{2} +1

please note that the division by the modulus above we used

\frac{x^{5}+2x^{3}+x^{2} +1  }{x^{4}+x+1}= x+\frac{2x^{3} +1}{x^{4}+x+1}

5 0
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PLEASE ANSWER HONESTLY (PLEASE BE HELPFULL I HAVE BEEN STUCK ON THIS PROBLEM) WILL MARK BRANIEST IF CORRECT. (no links my comput
motikmotik

Step-by-step explanation:

o2+a2=h2

100} h^{2}=(10ft)^{2} +(17ft)^{2}

h2=100ft2+289ft2

h=389ft2−−−−−√

→19.7ft

this is an example on how to do it

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3 years ago
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