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Stolb23 [73]
3 years ago
9

An object is moving around the unit circle with parametric equations x(t)=cos(t), y(t)=sin(t), so it's location at time t is P(t

)=(cos(t),sin(t)) . Assume 0 < t < π/2. At a given time t, the tangent line to the unit circle at the position P(t) will determine a right triangle in the first quadrant. (Connect the origin with the y-intercept and x-intercept of the tangent line.)(a) The area of the right triangle is a(t)= 1/(2sin(x)cos(x)
(b)

lim

t ? pi/2?

a(t)= +infinity


(c)

lim

t ? 0+

a(t)= -infinity


(d)

lim

t ? pi/4

a(t)= 1


(e) With our restriction on t, the smallest t so that a(t)=2 is ??

(f) With our restriction on t, the largest t so that a(t)=2 is ??

(g) The average rate of change of the area of the triangle on the time interval [?/6,?/4] is ??

(h) The average rate of change of the area of the triangle on the time interval [?/4,?/3] is ??

(i) Create a table of values to study the average rate of change of the area of the triangle on the time intervals [?/6,b], as b approaches ?/6 from the right. The limiting value is -4/3

(j) Create a table of values to study the average rate of change of the area of the triangle on the time intervals [a,?/3], as a approaches ?/3 from the left. The limiting value is 4/3

Mathematics
1 answer:
Alexxandr [17]3 years ago
4 0

Answer:

See explaination

Step-by-step explanation:

Please kindly check attachment for the step by step solution of the given problem.

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A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
uysha [10]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

h(x)=ax(x-7)             ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

4=a(3)((3)-7)

4=a(3)(-4)

\dfrac{4}{(3)(-4)}=a

-\dfrac{1}{3}=a

Putting a=-\dfrac{1}{3}, we get

h(x)=-\dfrac{1}{3}x(x-7)              ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

Since h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

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So the drawings will have:

4 x 1/24 = 0'167 feet
6 x 1/24 = 0'25 feet
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</span>
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Answer:

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What is the mean absolute deviation of the following set of data 10 4 12 4 2 10 10 6
mart [117]

The mean absolute deviation of the given data 10, 4, 12, 4, 2, 10, 10, 6 is 3.1875.

According to the given question.

The given data set is

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Mean of the given data set  

= (10 + 4 +  12 + 4 + 2 + 10 + 10 + 6)/8

= 7.25

Now, the absolute values are:

|10 - 7.25| = 2.75

|4 - 7.25| = 3.25

|12 -7.25| = 4.25

| 4 - 7.25| = 3.25

| 2 - 7.25| = 5.25

| 10 - 7.25| = 2.75

| 10 - 7.25| = 2.75

| 6 - 7.25| = 1.25

The average of all absolute values

= (2.75 + 3.25 + 4.25 + 3.25 + 5.25 + 2.75 + 2.75 + 1.25)/8

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Therefore, the mean absolute deviation of the given data 10, 4, 12, 4, 2, 10, 10, 6 is 3.1875.

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