<h3>
Answer: -20</h3>
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Work Shown:
Let x be the location of E on the number line.
Since C is the midpoint of E and F, this means we can find C's location by adding E and F together and dividing that sum by 2
midpoint = (endpoint1 + endpoint2)/2
C = (E+F)/2
Plug in E = x, C = -8 and F = 4. Then solve for x
C = (E+F)/2
-8 = (x+4)/2
(x+4)/2 = -8
x+4 = 2(-8) .... multiplying both sides by 2
x+4 = -16
x = -16-4 .... subtract 4 from both sides
x = -20
The location of point E on the number line is -20
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As a check, lets add E and F to get E+F = -20+4 = -16
Then cut this in half to get -16/2 = -8, which is the proper location of point C
This confirms our answer.
Answer:
x=12
Step-by-step explanation:
For the given situation , a quantity x is added to 
gives 15.
We can set up equation as
Multiply each term by 4 on both sides to get rid the denominator.
It gives,
4 x+x=60
Now, combine like terms
5 x=60
Divide both sides by 5
x=12.
The volume goes up by a factor of 2 * 2 * 3 = 12 times.
Answer:
Step-by-step explanation:
She has 28056 before any deductions are taken off. As far as the IRS is concerned every penny she earns is fully accountable for the 4 categories that she has to pay into.
The problem with the question is you are not told what is wanted. Do they want the income before or after the deductions have been made or do they want the accountable sum (28056)? I don't really know. 28056 is one possible answer.
Total deductions
- Federal Tax 3780.90
- State Tax 770.98
- Medicare 406.81
- SSI <u>1739.47</u>
- All Deductions 6698.16
Income = 28056 - 6698.16 = 21357.84
I think the answer you want is 28056
One answer it is not is 4*28056 = 112224. The tax is far too low for that kind of income.
Answer:
the equation should be corrected to fit the data of the problem. With the corrected equation a mass of 0.5 grams remains after 150 years
Step-by-step explanation:
for the mass y( in grams)
y=23* (1/2)^(t/45), t ≥ 0.
the initial mass is at t=0 , then
y= 23 grams → should be 16 grams
half-life from the equation = 45 years → should be 30 years
the correct equation should be
y=16*(1/2)^(t/30), t ≥ 0
then after 150 years → t= 150
y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams
then a mass of 0.5 grams remains after 150 years
