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never [62]
4 years ago
8

The legs of a right triangle have lengths of 4 and 5 units. Find the length of the hypotenuse.

Mathematics
2 answers:
Ugo [173]4 years ago
8 0
For this we will want to use the Pythagorean Theorem. Lets plug our values in.

5^2+4^2=c^2

Our first step is to find out our squared values. 

25+16=^2.

You will then want to combine like terms.

41=c^2

Since C has a square, we will want to get rid of the squared. The opposite of squaring something is taking the square root of something.

We will then want to take the square root of 41.
Your final answer will be

C= 6.4
AVprozaik [17]4 years ago
3 0
You would use the Pythagorean threroem 4^2 + 5^2 = C^2. 16 + 25 = 41 the square root of 41 is 6.40
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Answer:

Some students were asked how many books they were carrying in their backpacks. The data is given in this frequency table. What is the mean number of pens carried by these students in their backpacks?

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0                 4

1                 5

2                 8

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3 years ago
Arthur starts his first workout routine by doing 10 push-ups. Each workout after the first, he plans to do 2 more push-ups than
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3 years ago
The SAT scores have an average of 1200 with a standard deviation of 60. A sample of 36 scores is selected. a) What is the probab
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Answer:

a) 0.0082

b) 0.9987

c) 0.9192

d) 0.5000

e) 1

Step-by-step explanation:

The question is concerned with the mean of a sample.  

From the central limit theorem we have the formula:

z=\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }

a) z=\frac{1224-1200}{\frac{60}{\sqrt{36} } }=2.40

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The area to the right of z=2.40 is 1-0.9918=0.0082

\therefore P(\bar X\:>\:1224)=0.0082

b) z=\frac{1230-1200}{\frac{60}{\sqrt{36} } }=3.00

The area to the left of z=3.00 is 0.9987

\therefore P(\bar X\:

c) The z-value of 1200 is 0

The area to the left of 0 is 0.5

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The area to the left of z=1.40 is 0.9192

The probability that the sample mean is between 1200 and 1214 is

P(1200\:

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e) z=\frac{73.46-1200}{\frac{60}{\sqrt{36} } }=-112.65

The area to the left of z=-112.65 is 0.

The area to the right of z=-112.65 is 1-0=1

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