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Nimfa-mama [501]
3 years ago
14

Determine the length of the longest piece of timber which could be stored in a rectangular shed 6cm by 5cm by 2m high​

Mathematics
2 answers:
Brut [27]3 years ago
6 0

Answer:

6 90u7 jhi

Step-by-step explanation:

Sladkaya [172]3 years ago
4 0

Answer:

200.2

Step-by-step explanation:

I would hate to own such a shed. It's not very big.

2 meters = 2 * 100 cm = 200 cm

The diagonal of the floor is the diagonal of 6cm by 5cm. Using a^2 + b^2 = c^2

5^2 + 6^2 = 25 + 36 = 61

The square root of 61 is 7.81 cm

Now the diagonal of the floor diagonal and the height

a^2 + h^2 = board^2

61 + 200^2 = board^2

61 + 40000 = board^2

40061 = board^2

sqrt(board^2) = sqrt(40061)

board = 200.2cm long.

Maybe you should check the question for units.

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Simplify the radical expression ⁴√625x¹²y⁸<br><br>Not sure if it's A or D PLEASE HELP ​
Maslowich

Answer:

Step-by-step explanation:

I think it could be D

Sorry if not correct

4 0
3 years ago
In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experien
diamong [38]

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = \frac{P(B|A)P(A)}{P(B)} = \frac{P(B|A)P(A)}{P(B|A)P(A) + P(B|a)P(a)}

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A  

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2  = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) =\frac{P(N|B1)P(B1)}{P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)} = \frac{(0.297)(0.3)}{(0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)} = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

4 0
3 years ago
Micahdisu please help
skad [1K]

Answer:

1) A - 42°

2) 74°

3) B - 45°

4) B - 66°

Step-by-step explanation:

1) E = D+H

87 = 45 + H

H = 42°

2) 180 - 50 - D

D = 180 - 44 - 62 = 74°

3) F = 105

H = 180-105 = 75

I + H = C + E

I + 75 = 83 + 37

I = 45°

4) D = 180 - (E + F)

D = 180 - (30 + 57) = 93°

93 = A + 27

A = 66°

4 0
3 years ago
Read 2 more answers
From class we learned that in 2010 the federal debt (in millions) was $13,561,623 and the population of the U.S. was 309 million
Crank
According to these numbers, in 2010 the federal debt per capita was $43,888.75. Hope this helps!
6 0
3 years ago
Read 2 more answers
This table of values represents a linear function.
Vesna [10]
4.5 to 6.5 i think not really shure

3 0
3 years ago
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