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2 years ago

REPOST*

Mathematics

2 answers:

xeze [42]2 years ago

7 0

-6-3-5

Hence inequality will be

$\\ \sf\longmapsto -6\leqslant 5$

#2.

But we need inequality

$\\ \sf\longmapsto 3\leqslant 5$

The inequality given by

$\\ \sf\longmapsto -6\leqslant 3\leqslant 5$

Taya2010 [7]2 years ago

7 0

Answer:

See below

Step-by-step explanation:

<u>Given numbers:</u>

-6, 3 and 5

If we add these onto number line, we'll see them in same order from left to right.

We know the numbers increase from left to right on the number line, so the numbers to the left are smaller than the numbers to the right.

-6 < 3, as -6 is to left from 3

3 < 5, as 3 is to left from 5

-6 < 3 < 5, as per above explanation

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5. When looking at a map, a student realizes that Birmingham is nearly due west of Atlanta, and Nashville is nearly due north of

leonid [27]

Answer: 250 mi

Step-by-step explanation:

Here we can think in a triangle rectangle:

The distance from Birmingham to Atlanta is roughly 150 mi, and this is one of the cathetus.

And the distance from Birmingham to Nashville is roughly 200 mi, this is the other cathetus of the triangle.

Now, the distance from Atlanta to Nashville will be the hypotenuse of this triangle rectangle.

Now we can apply the Pythagorean's theorem:

A^2 + B^2 = H^2

Where A and B are the cathetus, and H is the hypotenuse:

Then:

H = √(A^2 + B^2)

H = √(150^2 + 200^2) mi = √(62,500) mi = 250 mi

Then the estimated distance from Atlanta to Nashville is 250 mi

6 0

3 years ago

What is the approximate solution of the linear system represented by the graph below

VashaNatasha [74]

ANSWER

The approximate solution is

$(4, - 1)$

EXPLANATION

The point of intersection of the two lines is the solution of the linear systems represented by the graph.

From the graph we can determine that each box is 2 units.

From the graph, when we start at O and count two boxes to the right and half box down, we obtain the point of intersection of the two lines to be
$(4, - 1)$

Note that since each box is two units, half way between the boxes gives one unit.

5 0

3 years ago

I don't know how to do this or what i'm doing plz help

mote1985 [20]

recalling that d = rt, distance = rate * time.

we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?

$\bf \begin{array}{ccll} miles&hours\\ \cline{1-2} 12&1\\ 18&x \end{array}\implies \cfrac{12}{18}=\cfrac{1}{x}\implies 12x=18\implies x=\cfrac{18}{12}\implies x=\cfrac{3}{2}$

so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.

then Wanda kicks in, rolling like a lightning at 16mph.

let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.

the distance both have travelled is the same "d" miles, reason why they "meet", same distance.

$\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}$

$\bf \stackrel{\textit{substituting \underline{d} in the 2nd equation}}{\boxed{(12)\left( t+\frac{3}{2} \right)}=16t}\implies 12t+18=16t \\\\\\ 18=4t\implies \cfrac{18}{4}=t\implies \cfrac{9}{2}=t\implies \stackrel{\textit{four and a half hours}}{4\frac{1}{2}=t}$