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MissTica
3 years ago
13

eric has been donating books he no longer needs to his local library. after 3 months of donating, he had 157 books left in his r

oom. after 8 months of donating, he had 102 books left in his room. how many books per month did eric donate on average between monhs 3 and 8?

Mathematics
2 answers:
Akimi4 [234]3 years ago
6 0
157 - 102 = 55
-----------------------
8-3 = 5

55/5 = 11 books
chubhunter [2.5K]3 years ago
5 0
He donated 18 books per month. you first finds the difference of the books then do use the number of books by the number of months (in this case it was 5 months)
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joe is in debt $250, but he's saving $30 each month. using the equation, y=30x-250, how long will it take joe to have $230?
Vsevolod [243]

Answer:

16

Step-by-step explanation:

so in this equation we have 2 variables, and we must figure out what those variables mean:

y: "y" is the total amount of money joe has after subtracting his debt from it

x: "x" is the # of months as the cost of each month(30) is placed just before this variable

as y is the total amount of money joe has we need to substitute it for 230 to figure out how long it took for joe to recieve that much money

230=30x-250

480=30x

x=16

it took joe 16 months to get $230

3 0
3 years ago
France Under Louis XVI
enot [183]

Answer:

thx

Step-by-step explanation:

4 0
2 years ago
A star in the sky appears to move by 12 arcseconds over the course of 6 months. Convert this number into first areminutes then d
Bumek [7]

Answer:

Given :A star in the sky appears to move by 12 arc seconds over the course of 6 months.

To Find :Convert this number into first arc minutes then degrees.

Solution:

60 arc seconds = 1 arc minute

1 arc seconds = \frac{1}{60} arc minute

12 arc seconds = \frac{1}{60} \times 12 arc minute

12 arc seconds = \frac{1}{5} arc minute

So, 12 arc seconds = \frac{1}{5} arc minute

Now convert it into degrees

60 arc minute = 1 degree

1 arc minute = \frac{1}{60} degree

\frac{1}{5} arc minute = \frac{1}{60} \times \frac{1}{5} degree

\frac{1}{5} arc minute = \frac{1}{300} degrees

12 arc seconds = \frac{1}{300} degrees

8 0
3 years ago
Rewrite the expression x^3+10x^2+13x+39/x^2+2x+1 in the form of q(x)+r(x)/b(x)
natima [27]

\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}

x^3=x\cdot x^2, and x(x^2+2x+1)=x^3+2x^2+x. Subtracting this from the numerator gives a remainder of

(x^3+10x^2+13x+39)-(x^3+2x^2+x)=8x^2+12x+39

8x^2=8\cdot x^2, and 8(x^2+2x+1)=8x^2+16x+8. Subtracting this from the previous remainder gives a new remainder of

(8x^2+12x+39)-(8x^2+16x+8)=-4x+31

-84x is not a multiple of x^2, so we're done. Then

\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}=x+8+\dfrac{-4x+31}{x^2+2x+1}

4 0
2 years ago
△PQR is similar to △STU . In addition, m∠U=96° and m∠T=6(m∠P) . What is m∠P ? Enter your answer in the box. °
kenny6666 [7]
<span>△PQR is similar to △STU

</span>m∠R = m∠U = 96°

m∠Q = m∠T = 6

m∠P = 180 - ( 96 + 6)

m∠P = 180 - 102

m∠P = 78
 
answer 

m∠P = 78
7 0
3 years ago
Read 2 more answers
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